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3 years ago

Which equation does the graph of the systems of equations solve? 2 linear graphs. They intersect at 1,4

Mathematics

1 answer:

Pepsi [2]3 years ago

6 0

Answer:

See below.

Step-by-step explanation:

There is an infinite n umber of systems of equations that has (1, 4) as its solution. Are you given choices? Try x = 1 and y = 4 in each equation of the choices. The set of two equations that are true when those values of x and y are used is the answer.

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Evaluate the following expressions by substituting s = 5 and t = 4.

s344n2d4d5 [400]

$\huge\text{Hey there!}$

$\huge\textbf{Equation:}$

$\mathbf{4t^2 - 2t - s}$

$\huge\textbf{Solving:}$

$\mathbf{4t^2 - 2t - s}$

$\mathbf{= 4(4)^2 - 2(4) - 5}$

$\mathbf{= 4(4\times 4) - 2(4) - 5}$

$\mathbf{= 4(16) - 2(4) - 5}$

$\mathbf{= 64 - 2(4) - 5}$

$\mathbf{= 64 - 8 - 5}$

$\mathbf{= 56 - 5}$

$\mathbf{= 51}$

$\huge\textbf{Answer:}$

$\huge\boxed{\textsf{Option B. 51}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h3>~ $\frak{Amphitrite1040:)}$ </h3>

4 0

2 years ago

PLEASE HELP!!!! THIS IS MY LAST QUESTION!!!

Novay_Z [31]

Answer:

Step-by-step explanation:

1-3 2-4 5-2 4-1

8 0

3 years ago

Read 2 more answers

— 3х – 2y = 16<br> х+ 9y = 28

Alla [95]

Answer:

x=-8

y=4

Step-by-step explanation:

first you multiply this equation (-3x-2y=16) with negativ it will be like this 3x+2y=-16

3x+2y=-16

(x+9y=28)3 _multiply with 3

3x+2y=-16

3x+27y=84

use minus(-) =3x-3x=0

=2y-27y=-25y

=-16-84=-100

the result:-25y=-100

y=4

take any simple equation and replace y with 4

x+9y=28

x+9(4)=28

x+36=28

x=28-36

x=-8

answer:x=-8,y=4

5 0

3 years ago

Suppose that you play the game with three different friends separately with the following results: Friend A chose scissors 100 t

Yanka [14]

Answer:

Friend A

$\hat p_A= \frac{100}{400}=0.25$

$z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47$

Friend B

$\hat p_B= \frac{20}{120}=0.167$

$z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80$

Friend C

$\hat p_C= \frac{65}{300}=0.217$

$z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17$

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of scissors selected for each friend

$\hat p=\frac{X}{n}$ estimated proportion of scissors selected for each friend

$p_o=\frac{1}{3}=0.333$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion that the friend will pick scissors is less than 1/3 or 0.333, the system of hypothesis would be:

Null hypothesis: $p\geq 0.333$

Alternative hypothesis: $p < 0.333$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

Friend A

$\hat p_A= \frac{100}{400}=0.25$

$z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47$

Friend B

$\hat p_B= \frac{20}{120}=0.167$

$z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80$

Friend C

$\hat p_C= \frac{65}{300}=0.217$

$z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17$

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

6 0

4 years ago

Explain how the segment addition postulate can be modeled using a real world object

Kazeer [188]

You could model a strait road by using a segment addition postulate. For instance, if you are between point A and B you could calculate how much future you need to go by subtracting the length of the road by the distance you have traveled. Also, segment addition postulate can be used with City Water Lines or Sewer Lines. They can be used to calculate how much pipe is damaged and needs to be replaced.

6 0

3 years ago