Answer
1) true
2)false
3)false
4)true
5)true
Step-by-step explanation:
The equation that is equivalent to S=pi r^2 h is h = S/pir^2
<h3>Subject of formula</h3>
This is a way of representing a variable with another. Given the equation
S=pi r^2 h
We are to make 'h" the subject of the formula.
Divide both sides by pir^2
S/pir^2 =pi r^2 h/pir^2
h = S/pir^2
Hence the equation that is equivalent to S=pi r^2 h is h = S/pir^2
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Answer:
Step-by-step explanation:
x-y=11
2x+y=19
---------------
x=y+11
2(y+11)+y=19
2y+22+y=19
3y+22=19
3y=19-22
3y=-3
y=-3/3
y=-1
x-(-1)=11
x+1=11
x=11-1
x=10
Answer: x=10, y=-1. (10, -1).
-----------------------------------------
-6x+5y=1
6x+4y=-10
-------------------
9y=-9
y=-9/9
y=-1
6x+4(-1)=-10
6x-4=-10
6x=-10+4
6x=-6
x=-6/6
x=-1
Answer: x=-1, y=-1. (-1, -1).
------------------------------------
2x+9y=25
-4x-9y=-23
-------------------
-2x=2
x=2/-2
x=-1
2(-1)+9y=25
-2+9y=25
9y=25-(-2)
9y=25+2
9y=27
y=27/9
y=3
Answer: x=-1, y=3. (-1, 3).
Answer:
isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.
Step-by-step explanation:
Let
denote a set of elements.
would denote the set of all ordered pairs of elements of
.
For example, with
,
and
are both members of
. However,
because the pairs are ordered.
A relation
on
is a subset of
. For any two elements
,
if and only if the ordered pair
is in
.
A relation
on set
is an equivalence relation if it satisfies the following:
- Reflexivity: for any
, the relation
needs to ensure that
(that is:
.)
- Symmetry: for any
,
if and only if
. In other words, either both
and
are in
, or neither is in
.
- Transitivity: for any
, if
and
, then
. In other words, if
and
are both in
, then
also needs to be in
.
The relation
(on
) in this question is indeed reflexive.
,
, and
(one pair for each element of
) are all elements of
.
isn't symmetric.
but
(the pairs in
are all ordered.) In other words,
isn't equivalent to
under
even though
.
Neither is
transitive.
and
. However,
. In other words, under relation
,
and
does not imply
.
Answer:
the second option and x=20