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Dima020 [189]
2 years ago
13

-4x+5>-5 solve the equation is it greater than or less than

Mathematics
1 answer:
ladessa [460]2 years ago
5 0

Answer:

x>5/2

Step-by-step explanation:

-4x+5>-5

-4x>-10

4x>10

x>10/4

x>5/2

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What is the measure of angle c in degrees? *<br> 150<br> 30<br> 90<br> 60
Dmitry [639]

Answer:

Option (2)

Step-by-step explanation:

Measure of angle formed by two tangents from a point outside the circleis half the difference of the measures of the intercepted arcs.

From the figure attached,

m∠C = \frac{1}{2}[m(\text{major arc AB})-m(\text{minor arc AB)}]

        = \frac{1}{2}[(360-m\widehat{AB})-m(\widehat{AB})]

        = \frac{1}{2}[360-2m(\widehat{AB})]

        = 180-m\widehat{AB}

        = 180 - 150

        = 30°

Therefore, measure of angle C will be 30°.

Option (2) is the answer.

4 0
3 years ago
On its first visit to the vet, Emma’s kitten weighed 30 ounces. On its second visit, the kitten had gained 8 ounces. On its thir
IrinaK [193]

Answer:

46.667% increase of 30.

Step-by-step explanation:

44 is a 46.667% increase of 30.

7 0
3 years ago
Read 2 more answers
2. The electrical resistance R of a wire varies inversely with the square of its diameter d. If a wire with a
Mariulka [41]

Answer:

0.225 \Omega =225 m\Omega

Step-by-step explanation:

We know (Ohm second law) that R= \frac{k}{d^2} where k inlcudes the rest of the parameters (material, lenght). In our situation we have k= 0.4\cdot9 \Omega mm^2. The moment the diameter becomes 8mm R becomes

R= {{0.4\cdot 9}\over{16}} \Omega = 0.225 \Omega

4 0
2 years ago
You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us
Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that    

step 1

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

r=10\%=10/100=0.10\\n=4  

substitute in the formula above

A=P(1+\frac{0.10}{4})^{4t}  

A=P(1.025)^{4t}  

Applying property of exponents

A=P[(1.025)^{4}]^{t}  

A=P(1.1038)^{t}  

step 2

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

r=10\%=10/100=0.10  

substitute in the formula above

A=P(e)^{0.10t}  

Applying property of exponents

A=P[(e)^{0.10}]^{t}  

A=P(1.1052)^{t}  

step 3

Compare the final amount

P(1.1052)^{t} > P(1.1038)^{t}

therefore

Find the difference

P(1.1052)^{t} - P(1.1038)^{t} ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0
3 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
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