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marta [7]
3 years ago
6

I need help on this worksheet for my math hw it’s combing like terms?

Mathematics
1 answer:
maw [93]3 years ago
3 0
What you would do is combine the terms with variables, and combine the terms without.

Answers:
2. -2w-22
3. 15z
4. 7-16s
5. 17w
6. 4-6r
7. 21-8b
8. 8q
9. -18q-9
10. 12q-3

I hope I got all of these right if not that’s embarrassing haha I did all of them in my head I’m pretty sure they’re right

I hope I helped
You might be interested in
What is the remainder in the synthetic division problem
denis-greek [22]

Answer:

C

Step-by-step explanation:

1 | 4   6   - 2

        4     10

  ------------------

   4   10    8 ← remainder

 

3 0
3 years ago
Read 2 more answers
i used the answer key to get my answer and checked it with my dumb useless teacher and it’s right but, he won’t tell me how to g
gizmo_the_mogwai [7]
You multiply it with the same number you use for the denominator.
in this case 3/4 and 7/10
you find the LCM of the denominator is 20
so for 4 to become 20 you multiply by 5 then for the numerator 3 also multiply by 5, so you get 15/20
its the same also with 7/10, you multiply both the numerator and the denominator by 2 and get 14/20
hope it help... :)




7 0
3 years ago
The graph of a linear function passes through the points (-
myrzilka [38]

Answer:

3/5

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - (-4) / 2 - (-3)

3/5

3/5 is the slope.

5 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
Jeleah is buying a dress for her
defon

Answer: 58.4

Step-by-step explanation:

63 - 4.60 = 58.4

plz mark brainliest

4 0
3 years ago
Read 2 more answers
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