Question

(4x-3)(2x^2-7x+1) what is the product of this please help!

Answer 1

Answer:

$8x^{3}-34x^{2}+25x-3$

Step-by-step explanation:

In order to solve this problem, lets take the two terms in the binomial (4x and -3) and, for each one, multiply them by each term in the trinomial (2x^2, -7x, and 1):

$(4x-3)(2x^{2}-7x+1)$

$(4x*2x^{2})+(4x*-7x)+(4x*1)+(-3*2x^{2})+(-3*-7x)+(-3*1)$

$8x^{3}+(-28x^{2})+4x+(-6x^{2})+21x+(-3)$

$8x^{3}-28x^{2}+4x-6x^{2}+21x-3$

Let's combine like terms to get our final answer:

$8x^{3}-28x^{2}-6x^{2}+4x+21x-3$

$8x^{3}-34x^{2}+25x-3$