Answer:
The farmer would need 80 posts.
Step-by-step explanation:
If one side of the garden is 10m long, and the garden is a square, we can assume that all 4 sides will be 10m. That makes it 40m in total. Times 40×2 and you get 80.
I think Theodosius the best measure. The outliers will not effect the measure. If you use mean, you add all the data points and divide by the number of data points. The extremes will skew the data. If you use mode, that may work also. You find the data that occurs most often.
Let 'x' be the distance from THE far bank where 700 is the distance to the NEAR bank
boat one has travelled 700 (rate = 700/unit time) boat two has travelled x rate = x / unit time
boat one then travels x + 400 more and boat two travels 700 + (700+x -400) more when they meet
The time is the same rate x time = distance distance/rate = time equate the distances divided by the respective rates
(700 + x + 400)/700 = ( x + 700 + (700+x-400) )/x
1100x + x^2 = 1400x + 700000
x^2-300x -700000 = 0 quadratic formula yields x = 1000
One boat travels 700 the other 1000 whe they first meet.....width of river = 700+ 1000 = 1700 m
Answer:
This is a hardbut I think the awnser is C
Step-by-step explanation:
This usually happens when a person think that the others are incapable of actullay figuring out he problems .
