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1 year ago

How many solutions would the system of equations y=2x+2 and y=6x+2 have

Mathematics

2 answers:

Llana [10]1 year ago

8 0

Answer:

One solution

Step-by-step explanation:

Set the equations equal to each other and solve for x:

$y=2x+2,y=6x+2\\\\2x+2=6x+2\\2=4x+2\\0=4x\\x=0$

Therefore, there is only one solution

pickupchik [31]1 year ago

7 0

Answer:

Only one solution

Step-by-step explanation:

y = 2x + 2 -------------(I)

y = 6x + 2 --------------(II)

Substitute y =6x + 2 in equation (I)

6x + 2 = 2x +2

6x = 2x + 2 - 2

6x = 2x

6x - 2x = 0

4x = 0

x = 0

Plugin x = 0 in equation (I)

y = 2*0 +2

y = 2

Solution: (0,2)

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777dan777 [17]

Answer:

6x > 3+4(2x -1)

6x > 3+ 8x - 4

6x > (-1) + 8x

6x - 6x > (-1) + 8x - 6x

subtracting 6x from both sides

0 > 2x - 1

adding +1 on both sides

1 > 2x

1/2 > x

x < 1/2

5 0

2 years ago

Read 2 more answers

Suppose that the halflife of a substance is 250 years . If there were ir 100 the substance , (a) give an exponential model for t

IgorLugansk [536]

After 500 years one would have N nuclei of the original substance.

N = 100 * exp ( -ln(4) ) = 25

LOL.

I guess it is exp( - lamda * t)

Lamda, the decay constant is the ln(2) over the half life.

So we get exp( -ln(2)/250 * 500) or exp ( -ln(4) )
690 viewsView 1 Upvoter
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