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Mice21 [21]
3 years ago
13

What is the missing term that makes these ratios equivalent? 1.5:3, 31.5:____

Mathematics
1 answer:
Juliette [100K]3 years ago
6 0
<h3>Answer:  63</h3>

=========================================

Work Shown:

1.5/3 = 31.5/x

1.5x = 3*31.5  cross multiply

1.5x = 94.5

x = 94.5/1.5  dividing both sides by 1.5

x = 63

-----------

An alternative equation to solve is

1.5/31.5 = 3/x

1.5x = 31.5*3

1.5x = 94.5

The remainder of the steps are the same as in the previous section above.

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It’s the same thing as 55.5 - 200
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Can someone help me with this problem? It’s Special Right Triangles: Decimal Answer. Round to the nearest tenth. Thank you ! 10
Triss [41]

Answer:

h = 1.4

c = 2.8

Step-by-step explanation:

For each problem, remember the special triangle side ratios then use a proportion. To solve, isolate the variable.

For the triangle with the variable h:

Since two of the angles are 45, this is an isosceles triangle. All isosceles triangles have two equal sides that are not the hypotenuse.

In a right isosceles triangle, the ratio for regular side to hypotenuse is 1 to √2.

\frac{1}{\sqrt2} =\frac{h}{2} \\h = 2\frac{1}{\sqrt2} \\h = \frac{2}{\sqrt2} \\h = \frac{2\sqrt2}{2} \\h = \sqrt{2}

h = √2

h ≈ 1.4

For the triangle with the variable c:

The is an equilateral triangle cut in half because the angles are 30 and 60.

The side ratio of altitude to hypotenuse is √3 to 2.

\frac{\sqrt{3} }{2} =\frac{c}{4} \\\sqrt{3} = \frac{c}{2}\\2\sqrt3 = c

c = 2√2

c ≈ 2.8

5 0
3 years ago
The general equation of the plane that contains the points (1, 0, 2), (−1, 1, −2), and the origin is of the form ax + by + cz =
ICE Princess25 [194]

Answer:

2x-z=0 is the equation of the plane.

Step-by-step explanation:

Given that the plane passes through the points (1,0,2) and (-1,1,-2)

and also origin.

Hence equation of the plane passing through three points we can use

Any plane passing through 3 given points is given as

\left[\begin{array}{ccc}x-x_1&y-y_1&z-z_1\\x_2-x_1&y_2-y_1&z_2-z_1\\x_3-x_1&y_3-y_1&z_3-z_1\end{array}\right] =0

Substitute the three points to get

\left[\begin{array}{ccc}x-1&y&z-2\\-1-1&1&-2-2\\0-1&0&0-2\end{array}\right] \\=0\\(x-1)(-2) -y(4-4)+(z-2)(1) =0\\-2x+z=0\\2x-z-=0

2x-z=0 is the equation of the plane.

4 0
4 years ago
Ill give stars if correct.
Hitman42 [59]
I think the first one is 4 dollars
Because 30 divided by 4
6 0
3 years ago
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