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3 years ago

What is the y-intercept of the line shown?

Mathematics

2 answers:

Daniel [21]3 years ago

8 0

The y intercept is +4 as the line crosses at y=4

Inga [223]3 years ago

3 0

That would be the point (0,4)

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Math question.

Oduvanchick [21]

Answer:

C) 25%

Step-by-step explanation:

let salt be 's'

let water be 'w'

$\frac{s+1}{w+s+1} = 33\frac{1}{3} \\\\\frac{s+1}{w+s+1} = \frac{1}{3} \\\\\frac{w + s + 1}{3} = s+1\\\\3s +3 = w+s+1\\w = 2s+2\\\\\frac{s+1}{w+1+s+1} = \frac{3}{10} \\\\\frac{3(w+s+2)}{10} = s+1\\\\3w+3s+6 = 10s+10\\**w = 2s+2\\3(2s+2) + 3s + 6 = 10s+10\\\\6s+6+3s+6 = 10s+10\\9s+12 = 10s+10\\-s = -2\\s = 2\\\\w= 2s+2\\w=2*2+2\\w = 6\\\\\frac{2}{2+6} = \frac{2}{8} = 0.25$

0.25 = 25%

7 0

2 years ago

What are the numbers in the smallest group of repeating digits when 41/11 is converted to a nonterminating decimal?

harkovskaia [24]

Answer:

Step-by-step explanation:

also im not really too sure on my answer so check other answers for a more reliable answer

7 0

3 years ago

Read 2 more answers

Arjun and Jessica each improved their yards by planting daylilies and shrubs. They bought their

Anvisha [2.4K]

Hi there! Let me know if you have questions about my answer:

One shrub is $11.

One daylily is $4.

Step-by-step explanation:

To find the cost of each item, write a system of equations, one equation for what each person bought, and solve for each variable.

Define your variables.

let 'd' be the cost of one daylily

let 'r' be the cost of one shrub

Create a system using the variables and information from the question.

Write an equation for what Arjun bought:

5d + 7r = 97 5 daylilies, 7 shrubs, totaling $97

Write an equation for what Jessica bought:

2d + 11r = 129 2 daylilies, 11 shrubs, totaling $129

Solve the system.

I will solve the system algebraically, using the substitution method. Isolate one variable in one of the equations.

I will isolate 'd' in Jessica's equation:

$2d + 11r = 129$ Start with Jessica's equation

$\frac{2d + 11r}{2} = \frac{129}{2}$ Divide everything in the equation by 2

$d + \frac{11r}{2} = \frac{129}{2}$ Simplify

$d = \frac{129}{2} - \frac{11r}{2}$ Isolate 'd' by subtracting $\frac{11r}{2}$ from both sides.

Now you have an expression for 'd'.

Substitute Arjun's equation with the expression for 'd'. Solve for 'r' to find the cost of one shrub.

$5d + 7r = 97$ Start with Arjun's equation

$5(\frac{129}{2} - \frac{11r}{2}) + 7r = 97$ Substitute 'd' for $d = \frac{129}{2} - \frac{11r}{2}$

$\frac{5*129}{2} - \frac{5*11r}{2} + 7r = 97$ Distribute the 5

$\frac{645}{2} - \frac{55r}{2} + 7r = 97$ Simplify the numerators

$\frac{645}{2} - \frac{55r}{2} + \frac{14r}{2} = 97$ Change 7r to a fraction over 2

$\frac{645}{2} - \frac{41r}{2} = 97$ Combine like terms, the terms with 'r'

$\frac{645-41r}{2} = 97$ Simplify

$645-41r = 194$ Multiply both sides by 2

$-41r = 194-645$ Subtract 645 from both sides

$-41r = -451$ Divide both sides by –41

$r = 11$ Solved for cost of one shrub

Substitute 'r' for 11 using either Arjun's or Jessica's equation. Then, isolate 'd' to solve for the cost of one daylily.

I will use Arjun's equation.

$5d + 7r = 97$ Start with Arjun's equation

$5d + 7(11) = 97$ Substitute 'r' for r = 11

$5d + 77 = 97$ Simplify. Subtract 77 from both sides.

$5d = 20$ Divide both sides by 5.

$d = 4$ Solved for the cost of one daylily

I hope this helped! Check out a similar problem about solving systems here to learn more:

brainly.com/question/11103098

7 0

3 years ago

Zach is 3 years older than twice his sister Maya’s age.

Flauer [41]

The answer is z=2m+3 so the first one is right

8 0

4 years ago

Read 2 more answers

Given a non-zero rational number, a, and an irrational number, b, what can be said about the product of a and b?

laiz [17]

Answer:

The product of a non-zero rational number and an irrational number is irrational.

7 0

2 years ago