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3 years ago

What is the y-intercept of the line shown?

Mathematics

2 answers:

Daniel [21]3 years ago

8 0

The y intercept is +4 as the line crosses at y=4

Inga [223]3 years ago

3 0

That would be the point (0,4)

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Jon drives at a constant rate of 60 miles per hour. He’s taking a trip and needs to drive 480 miles. Determine how many hours hi

Ne4ueva [31]

Answer:

8 hours.

Step-by-step explanation:

60x8=480

Hope this helps!

3 0

3 years ago

Read 2 more answers

50 POINTS FOR CORRECT AWNSER!

Grace [21]

Answer:

$\mathsf{y < \dfrac47x-4}$

Step-by-step explanation:

<u>First, find the equation of the line</u>.

<em>Slope-intercept form</em> of a linear equation: $\mathsf{y=mx+b}$

(where m is the slope and b is the y-intercept)

From inspection of the graph, the y-intercept is at (0, -4)

Therefore, b = -4

Choose another point on the line, e.g. (7, 0)

Now use the slope formula to find the slope:

$\mathsf{slope=\dfrac{y_2-y_1}{x_2-x_1}}$

where:

$\mathsf{(x_1,y_1)=(0,-4)}$
$\mathsf{(x_2,y_2)=(7,0)}$

$\implies \mathsf{slope=\dfrac{0-(-4)}{7-0}=\dfrac47}$

Therefore, the equation of the line is:

$\mathsf{y=\dfrac47x-4}$

For an inequality, the dashed line means < or > (whereas a solid line means ≤ or ≥)

As the shading is below the line, we need to use <

Therefore, the final inequality is:

$\mathsf{y < \dfrac47x-4}$

8 0

2 years ago

ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe

xxMikexx [17]

Answer:

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=654.16$ represent the sample mean

$\mu$ population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that $t_{\alpha/2}=2.02$