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kramer
3 years ago
8

What is 4X squared times X -4

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0

Answer:

4x^2-16x

Step-by-step explanation:

4x(x-4)

4x(x)-4x(4)

4x^2-16x

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Please help!!!!!
WARRIOR [948]

3)

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{-7}~,~\stackrel{y_2}{7}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ -7 -2}{2}~~~ ,~~~ \cfrac{ 7 + 9}{2} \right)\implies \left( \cfrac{-9}{2}~~,~~\cfrac{16}{2} \right)\implies \left( -4\frac{1}{2}~~,~~8 \right)

6 0
2 years ago
Write the Taylor Series for f(x) = sin(x)center
tangare [24]

Answer:

Taylor series of sin(x) centered at x = 0.

Step-by-step explanation:

Taylor series expansion:

\sum_{n=0}^N f^n(a)\displaystyle\frac{(x-a)^n}{n!}

Here, f(x) = sin (x) and a = 0

f(x) = \sin x, f(0) = 0\\f'(x) = \cos x, f'(0) = 1\\f''(x) = -\sin x, f''(0) = 0\\f'''(x) = -\cos x, f'''(0) = -1\\f^4(x) = \sin x, f^4(0) = 0\\f^5(x) = \cos x, f^5(0) = 0

Putting all the values and expanding, we get,

f(x) = f(a) + \displaystyle\frac{f'(a)(x-a)}{1!} + \displaystyle\frac{f''(a)(x-a)^2}{2!} + \displaystyle\frac{f'''(a)(x-a)^3}{3!} + \displaystyle\frac{f^4(a)(x-a)^4}{4!} + \displaystyle\frac{f^5(a)(x-a)^5}{5!} + ...\\\\= \sin 0 + \displaystyle\frac{x}{1!} +  \displaystyle\frac{(0)x^2}{2!} + \displaystyle\frac{(-1)x^3}{3!} + \displaystyle\frac{(0)x^4}{4!} + \displaystyle\frac{(1)x^5}{5!} + ...

Solving, we get

\sin x = x - \displaystyle\frac{x^3}{3!} + \displaystyle\frac{x^5}{5!} - \displaystyle\frac{x^7}{7!} + ...\\\\\sin x = x - \displaystyle\frac{x^3}{6} + \displaystyle\frac{x^5}{120} - \displaystyle\frac{x^7}{5040} + ...

3 0
3 years ago
What is the slope of the line that passes through 9,5 and 4,5
Vesnalui [34]

Answer:

0

Step-by-step explanation:

slope m = (y₂ - y₁) / (x₂ - x₁)

             = (5 - 5) / (4 - 9)

             = 0 / -5

             = 0

6 0
2 years ago
Read 2 more answers
Find the area of the rhombus if AE = 20 m and DE = 32 m
Fudgin [204]
We have to calculate the area of the rhombus if AE = 20 m and DE = 32 m.The diagonals DB = 2 * DE and AC = 2 * AE.
DB = 2 * 32 = 64 mAC = 2 * 20 = 40 mArea = d1 * d2 / 2 = DB * AC / 2 = 64 * 40 / 2 = 1,280 m²Answer: The area of the rhombus is B ) 1,280 m².
4 0
3 years ago
¿cuántas raíces cuadradas tiene el número 0?
DanielleElmas [232]

Answer:

one

Step-by-step explanation:

Zero has one square root which is 0.

Negative numbers don't have real square roots since a square is either positive or 0.

7 0
3 years ago
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