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sergiy2304 [10]
3 years ago
14

Sarita showed the steps to solving the equation. 5 (x minus 3) + 7 (x + 4) = 73 Steps Sarita’s Solution Sarita’s Verification 1

5 x minus 15 + 7 x + 28 = 73 5 (5 minus 3) + 7 (5 + 4) = 73. 5 (negative 2) + 7 (9) = 73. Negative 10 + 63 = 73. 53 not-equal-to 73. 2 (5 + 7) x + (negative 15 + 28) = 73 3 12 x + 13 = 73 4 12 x + 60 5 x = 5 When Sarita tried to verify her answer, she found it was wrong. Which explains her mistake? Sarita’s solution is correct. She made an error in her verification. Sarita was supposed to add the 5 and 7 in the first step. Sarita added +13 instead of Negative 13 in the fourth step. Sarita was supposed to use the division property of equality in the third step.

Mathematics
2 answers:
SVEN [57.7K]3 years ago
4 0

Answer:A

Step-by-step explanation:

Usimov [2.4K]3 years ago
3 0

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

Given the following equation:

5 (x-3) + 7 (x + 4) = 73

The steps to solve it are:

1. Apply the Distributive property:

5x-15+7x+28=73

2. Add the like terms:

12x+13=73

3. Subtract5 13 from both sides of the equation:

12x+13-(13)=73-(13)\\\\12x=60\\\\

4. Divide both sides of the equation by 12:

\frac{12x}{12}=\frac{60}{12}\\\\x=5

To verify it, let's substitute x=5 into the equation:

5 (5-3) + 7 (5 + 4) = 73

Evaluating, we get:

5 (2) + 7 (9) = 73\\\\10+63=73\\\\73=73

Based on this, we can determine that Sarita's solution is correct, but she made an error in her verification (Observe that  5-3\neq -2)

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Write an equation in slope intercept form of the line that passes through the given point and is paraell to the graph of the equ
Nostrana [21]
1.) x = -3...this is a vertical line with an undefined slope. A parallel line to a vertical line is also a vertical line. A vertical line is represented by x = a number....that number being the x coordinate of ur point(4,2).
so ur parallel line is : x = 4 <==
=================
2.) y = -3/2x + 6....slope here is -3/2. A parallel line will have the same slope.

y = mx + b
slope(m) = -3/2
(2,-1)...x = 2 and y = -1
now we sub into the formula and find b, the y int
-1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
so ur parallel line is : y = -3/2x + 2 <==
===================
y = -x - 2....the slope here is -1. A parallel line will have the same slope

y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub into the formula and find b, the y int
-2 = -1(2) + b
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0 = b
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8 0
3 years ago
A coin is tossed 5 times. Find the probability that all are heads. Find the probability that at most 2 are heads.
fenix001 [56]

Answer:

1/32

15/32

Step-by-step explanation:

For a fair sided coin,

Probability of heads, P(H) = 1/2

Probability of tails P(T)  = 1/2

For a coin tossed 5 times,

P( All heads)

= P(HHHHH),

= P (H) x P(H) x P(H) x P(H) x P(H)

= (1/2) x (1/2) x (1/2) x (1/2) x (1/2)

= 1/32 (Ans)

For part B, it is easier to just list the possible outcomes for

"at most 2 heads" aka "could be 1 head" or "could be 2 heads"

"One Head" Outcomes:

P(HTTTT), P(THTTT) P(TTHTT), P(TTTHT), P(TTTTH)

"2 Heads" Outcomes:

P(HHTTT), P(HTHTT), P(HTTHT), P(HTTTH), P(THHTT), P(THTHT), P(THTTH), P(TTHHT), P(TTHTH), P(TTTHH)

If we count all the possible outcomes, we get 15 possible outcomes representing "at most 2 heads)

we know that each outcome has a probability of 1/32

hence 15 outcomes for "at most 2 heads" have a probability of

(1/32) x 15  = 15/32

8 0
3 years ago
Read 2 more answers
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

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