X = 3 and CB = 19. To find x you would put 4x-9 + 3x+5 = 17. Remember to get all the x’s on one side and the other numbers on the other aide of the equal sign. Then plug x into the length of BC.
Take the derivitive
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?
Answer:
71°
Step-by-step explanation:
- 84+(2x-1)+(x+8)+(x+5)=360 [angles in a quadrilateral add to 360°]
- 4x+96=360 [combine like terms]
- 4x=264 [subtract 96 from both sides]
- x=66 [divide both sides by 4]
So, angle A measures 66+5=71°
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