The line, L1 passes through the points A (-3,-2) and B (3,-8) Find the gradient of L1.
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Option B. y = 3 (one-third) Superscript x is the function that is graphed in this question.
<h3>How to solve the problem</h3>We have exponential functions to be of the form abˣ
This can be written in the form of f(x) =
So it crosses through the point (0, 3).
From the way that the curve passes through the circle, we can see that the it is said to pass through at (0, 3) and approaches y = 0 in quadrant 1
Hence this would put our answer to be y = 3 (one-third) Superscript x
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