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3 years ago

Help with these problems

Mathematics

1 answer:

SVEN [57.7K]3 years ago

4 0

Answer:

1- D 2-A

number one: you multiply all the numbers together...

number two: you add the numbers together and i got A because if you add it all up, it is 42.593 and that is greater than 42.537.

hope dis helps! :p

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Step-by-step explanation:

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3 years ago

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3 years ago

If you want to be 95% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard

Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

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Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

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A samle size of at least n is required, in which n is found when $M = 3, \sigma = 20$

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$3 = 1.96*\frac{20}{\sqrt{n}}$

$3\sqrt{n} = 20*1.96$

$\sqrt{n} = \frac{20*1.96}{3}$

$(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}$

$n = 170.7$

Rouding up

The sample size required is at least 171

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3 years ago