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Nataly_w [17]
3 years ago
7

How do you solve this

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0
I cannot see it, please send another photo!
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Write an equation of a line that passes through (-12, -14) with slope 6.
damaskus [11]

The slope intercept form of a line is y = mx + b

  • m = slope
  • b = y-intercept

Plug in the slope, 6, into m.

Rewrite the equation;

  • y = 6x + b
  • We need to find b, your y-intercept, to finish this equation.

Plug in your point coordinate, (x, y) ⇒ (-12, -14) into the equation.

  • -14 = 6(-12) + b

Solve for b to find the y-intercept.

  • -14 = -72 + b
  • 58 = b

Your new equation (your answer) is<em> </em>y = 6x + 58.

6 0
3 years ago
Sarah spent a total of $7.25 on 8 apples and a packet of grapes. If a packet of grapes cost $2.85, how much did each apple cost?
Novosadov [1.4K]
$0.55 Cents per apple
Hope this helps
7 0
3 years ago
Hi bro sorry to bother you but I have a question it is ok . Ok then so 875x975=
mel-nik [20]

Answer:

853,125

Step-by-step explanation:

Umhhh u can use a calculator… or write it down and slowly break down solve it like that.

Hope this helps, good luck! ;)

4 0
3 years ago
Read 2 more answers
Sally rents a life jacket for a one-time fee of $5. She then rents a canoe for $15 per hour. Write an expression that represents
Mekhanik [1.2K]

Answer:

3.00/8

Step-by-step explanation:

because u simplify 15/5 and u get 3

4 0
3 years ago
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
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