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Lisa [10]
3 years ago
11

Find the sum and express it in simplest form (7n^3-9n)+(-8n^3+6n-3)

Mathematics
2 answers:
REY [17]3 years ago
7 0
-n^3 -3n +3 is the answer
the Check the image for steps.

Alexxx [7]3 years ago
3 0
<span>Reorder the terms: 6(-6 + 2n) + -3(7n + -10) = -9n + n (-6 * 6 + 2n * 6) + -3(7n + -10) = -9n + n (-36 + 12n) + -3(7n + -10) = -9n + n Reorder the terms: -36 + 12n + -3(-10 + 7n) = -9n + n -36 + 12n + (-10 * -3 + 7n * -3) = -9n + n -36 + 12n + (30 + -21n) = -9n + n Reorder the terms: -36 + 30 + 12n + -21n = -9n + n Combine like terms: -36 + 30 = -6 -6 + 12n + -21n = -9n + n Combine like terms: 12n + -21n = -9n -6 + -9n = -9n + n Combine like terms: -9n + n = -8n -6 + -9n = -8n Solving -6 + -9n = -8n Solving for variable 'n'. Move all terms containing n to the left, all other terms to the right. Add '8n' to each side of the equation. -6 + -9n + 8n = -8n + 8n Combine like terms: -9n + 8n = -1n -6 + -1n = -8n + 8n Combine like terms: -8n + 8n = 0 -6 + -1n = 0 Add '6' to each side of the equation. -6 + 6 + -1n = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1n = 0 + 6 -1n = 0 + 6 Combine like terms: 0 + 6 = 6 -1n = 6 Divide each side by '-1'. n = -6 Simplifying n = -6</span>
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The least total cost method (LTC) lot-sizing technique calculates the order quantity by comparing the carrying cost and the setu
rewona [7]

Answer:

True

Step-by-step explanation:

The least total cost method is the method in which the total cost of the ordering cost and the total carrying cost is equal among various lot size available.

The order quantity should be choose when the total ordering cost and the total carrying cost equal to each other

The formula to compute the economic order quantity is shown below:

a. The computation of the economic order quantity is shown below:

= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}

It is always be expressed in units

The formula to compute the ordering cost is

= \frac{Annual\ demand}{Economic\ order\ quantity}\times ordering\ cost\ per\ order

And, the formula to compute the carrying cost is

= \frac{Economic\ order\ quanity}{2}\times carrying\ cost\ per\ unit

Hence, the given statement is true

8 0
3 years ago
A simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and
Brrunno [24]

Answer:

.b. It is one‐half as large as when n = 100.

Step-by-step explanation:

Given that a  simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and a standard deviation of 3 hours.

i.e. s = 0.3

we obtain se of sample by dividing std devitation by the square root of sample size

i.e. s= \frac{3}{\sqrt{n} }

when n =100 this = 0.3 and

when n =400 this equals 0.15

We find that when sample size is four times as large as original, std deviation becomes 1/2 of the original

Correction option is

.b. It is one‐half as large as when n = 100.

7 0
3 years ago
What is the area of the paralleglogram 8.5cm and 11.4cm
Anon25 [30]

Answer:

96.9cm squared

Step-by-step explanation:

8 0
3 years ago
Find f(-2) for the function f(x)= 3x2-2x+7
4vir4ik [10]

Answer:

f( - 2) = 23

Step-by-step explanation:

f(x) = 3 {x}^{2}  - 2x + 7 \\ plug \: x =  - 2 \\ f( - 2) = 3 {( - 2)}^{2}  - 2( - 2)+ 7 \\  = 3 \times 4 + 4 + 7 \\  = 12 + 11 \\  \huge \red{ \boxed{ f( - 2) = 23}}

4 0
3 years ago
Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord
andrew-mc [135]
Consider the circle with center X, as shown in the figure. 

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is  

\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8 units.


Answer: 8 units

7 0
3 years ago
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