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3 years ago

Can someone pls help? Thx

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Your answer would be -3/4n+3/8 because 1/4•-3/1n would be -3/4n and then 1/4•3/2 would be 3/8 so your answer would then be -3/4n+3/8.

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HELP PLeaseeeee!!!!!!!

hram777 [196]

The correct answer is C.

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3 years ago

The poorest person in a country has 50$ and the richest had $9.956. How much less money does the poorest have

Alecsey [184]

What you need to do is subtract since the key word "How much Less money" is in it.

$9.956-$50 = 40.044$

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3 years ago

How many different 10 digit phone numbers are possible if numbers can be repeated

Stella [2.4K]

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3 years ago

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$

$(x^2-1)+(y^2-(-2))=16$

Now, we have that:

$h=1\\k=-2\\r=\sqrt{16}=4$

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0

3 years ago

What is the area of this

larisa86 [58]

Area of a triangle is base x height divide by 2
26x9=234
234 divide by 2 is 117

5 0

3 years ago