Ask question

Ask question

All categories

3 years ago

10

What is the slope intercept

1 answer:

Pie3 years ago

4 0

Answer:

rise is 20 and run is 5 so slope is 4.

I think the slope y-intercept is -5

You might be interested in

Answer?????????????????

Nostrana [21]

A1 = 6 a5 = -6

a1 + d(n-1) = -6

6 +4d = -6

4d = -12

d = -3

a3 = a2 + d = -6 -3 = -9

8 0

3 years ago

What is highest common factor of 98 and 42

ANEK [815]

The answer would be 14

5 0

3 years ago

Read 2 more answers

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

$f=z^3 -x^2y$

Firstly, we can find gradient

so, we will find partial derivatives

$f_x=0 -2xy$

$f_x=-2xy$

$f_y=0 -x^2$

$f_y=-x^2$

$f_z=3z^2$

now, we can plug point (-5,5,2)

$f_x=-2*-5*5=50$

$f_y=-(-5)^2=-25$

$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

7 0

4 years ago

Read 2 more answers

what is another way to write 297.3. Fill in: 2hundreds, 9tens, 5 ones + __________tenths I tried 2.3, but was told that was inco

Schach [20]

Maybe it is 23 tenths ???

7 0

3 years ago

How many inches are in 200 meters?

4vir4ik [10]

200×39.37=7874
the answer is 7874 in

3 0

3 years ago

Read 2 more answers