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likoan [24]
3 years ago
10

Find y when x = 15 if y = 6 when x = 30

Mathematics
1 answer:
Ivahew [28]3 years ago
6 0
Y is 12 you just multiply by 2 since 15 was multiplied by 2 as well
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Mr. K goes to the bank to withdraw some money. He requests that he only get $20 bills and $5 bills. Altogether, Mr. K got 30 bil
Vsevolod [243]

Answer:

10 $20 bills and 20 $5 bills

Step-by-step explanation:

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3 years ago
The ratio of a model scal die cast motorcycle is 1:18. the model is 5.25 inches long. what is the length of the actual motorcycl
Rudik [331]
1: 18 = 5.25/x
18(5.25)=1x
94.5=1x
94.5/1=1x/1
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4 0
3 years ago
What type of decimal is this fraction: LaTeX: \frac{11}{20}
skad [1K]

11/20

Divide 11 by 20 to find the decimal value.

11/20 = 0.55

The decimal only contains two numbers, so it is a terminating fraction.

6 0
3 years ago
What is the answer to f/3 < -2
Hitman42 [59]

Answer:

1 i think

Step-by-step explanation:

hope this helps :) have a nice day :) :)

4 0
3 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
1 year ago
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