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kow [346]
1 year ago
14

The length of a rectangle is 4yd longer than its width.

Mathematics
1 answer:
Monica [59]1 year ago
8 0

Answer:

Length= 19 yd

Width= 15 yd

Step-by-step explanation:

The perimeter of a rectangle is the sum of the lengths of all its sides.

Mathematically, it can be represented as below:

\boxed{\text{Perimeter of rectangle}=2\text{(length}+\text{width)}}

Define variables used:

Let the length and width of the rectangle be L and W yards respectively.

Form an equation:

Given that the length of the rectangle is 4 yards longer that the width,

L= W +4 -----(1)

Next, form another equation using information on the perimeter.

68= 2(L +W) -----(2)

Substitute equation (1) into (2):

68= 2(W +4 +W)

68= 2(2W +4)

Divide both sides by 2:

34= 2W +4

Subtract both sides by 4:

2W= 34 -4

2W= 30

Divide both sides by 2:

W= 30 ÷2

<u>W= 15</u>

Substitute W= 15 into (1):

L= 15 +4

<u>L= 19</u>

Therefore, the length and width of the rectangle is 19 and 15 yards respectively.

Additional:

For another question on perimeter of rectangle, check out: brainly.com/question/15528005

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