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kow [346]
2 years ago
14

The length of a rectangle is 4yd longer than its width.

Mathematics
1 answer:
Monica [59]2 years ago
8 0

Answer:

Length= 19 yd

Width= 15 yd

Step-by-step explanation:

The perimeter of a rectangle is the sum of the lengths of all its sides.

Mathematically, it can be represented as below:

\boxed{\text{Perimeter of rectangle}=2\text{(length}+\text{width)}}

Define variables used:

Let the length and width of the rectangle be L and W yards respectively.

Form an equation:

Given that the length of the rectangle is 4 yards longer that the width,

L= W +4 -----(1)

Next, form another equation using information on the perimeter.

68= 2(L +W) -----(2)

Substitute equation (1) into (2):

68= 2(W +4 +W)

68= 2(2W +4)

Divide both sides by 2:

34= 2W +4

Subtract both sides by 4:

2W= 34 -4

2W= 30

Divide both sides by 2:

W= 30 ÷2

<u>W= 15</u>

Substitute W= 15 into (1):

L= 15 +4

<u>L= 19</u>

Therefore, the length and width of the rectangle is 19 and 15 yards respectively.

Additional:

For another question on perimeter of rectangle, check out: brainly.com/question/15528005

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3 years ago
3.1(g-7)-1=5.2 what is G
dimulka [17.4K]

Answer:

g=9

Step-by-step explanation:

Add 1 to both sides of the equation t get 3.1(g-7)=6.2

Then divide both sides by 3.1 to get g-7=2

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4 0
3 years ago
What are the vertical asymptotes of the function f(x) = 4x+8/x^2+3x-4
Yuri [45]

Answer:

<em>1 and -4</em>

Step-by-step explanation:

<em>The vertical asymptote of a function is gotten by equating the denominator of such function to zero.</em>

Given

f(x) = 4x+8/x^2+3x-4

The vertical asymptotes is expressed as;

x^2+3x-4 = 0

Factorize

x^2+4x-x-4 = 0

x(x+4) -1 (x+4) = 0

(x-1)(x+4) = 0

x-1 = 0 and x+4 = 0

x = 1 and x = -4

<em>Hence the vertical asymptotes of the function are 1 and -4</em>

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3 years ago
(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =
jarptica [38.1K]

Answer:

See below.

Step-by-step explanation:

(5a^2 + 4ab – 3b^2) – (–5ab + 4b^2 + 3a^2)

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(5a^2-3a^2)+(4ab+5ab)+(-4b^2-3b^2)

2a^2+9ab-7b^2

-hope it helps

7 0
3 years ago
Read 2 more answers
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