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3 years ago

9

Is this a quadratic functions x = 3y2 – 6y + 5

1 answer:

S_A_V [24]3 years ago

8 0

-3y +2 2(-3y+2)+6y=5

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Select the correct answer. Which equation matches the function shown in the graph?

Kisachek [45]

Answer:

B) $y=sin(x+\frac{\pi}{2})$

Step-by-step explanation:

Technically, since the function starts at its maximum, you could say the function is $y=cos(x)$ , but the answer choices all use sine instead. Therefore, we will have to use the cofunction identity $cos(x)=sin(x+\frac{\pi}{2})$ and we can see that the correct answer is B.

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2 years ago

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AURORKA [14]

Answer:

y= -9

try desmos for questions like these it saved my life.

Step-by-step explanation:

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3 years ago

Add 7 and 3, then triple the result

Dovator [93]

Step-by-step explanation:

7 + 3

the Answer is 10

Then if we triple the result, we'll get 30

<em>1</em><em>0</em><em>*</em><em>3</em>

<em>3</em><em>0</em>

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2 years ago

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Wewaii [24]

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2 years ago

Find the term indecent of x in the expansion of (x^2-1/x)^6

Mars2501 [29]

By the binomial theorem,

$\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}$

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0 ===> 3k = 12 ===> k = 4

which corresponds to the constant coefficient

$\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}$

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