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3 years ago

at a basketball game, 6 adults pay $20 each and 4 children pay $10 each. What is the total cost for the adult tickets?

Mathematics

2 answers:

frez [133]3 years ago

7 0

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ The total cost for the adult tickets is $120.

There are 6 adults and each ticket is $20 so multiply the cost by the number of adults to find the cost for adults:

20 x 6 = 120

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

nlexa [21]3 years ago

5 0

Answer:

Step-by-step explanation:

$20* 6= 120

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2 years ago

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Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0

Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0

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Two Sample T Test:

t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}

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2 years ago

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Answer:

Step-by-step explanation:

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2 years ago

A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only

Semenov [28]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: Number of people that support the candidate.

You need to calculate the sample size to estimate the population proportion of supporters given a confidence level of 99% and a margin of error of 4%

The margin of error of the confidence level for the population proportion is

d= $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

From this formula you have to clear the value of n:

$\frac{d}{Z_{1-\alpha /2}}$ = $\sqrt{\frac{p'(1-p')}{n} }$

$(\frac{d}{Z_{1-\alpha /2}})^2$ = $\frac{p'(1-p')}{n}$

$n*(\frac{d}{Z_{1-\alpha /2}})^2$ = $p'(1-p')$

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sample proportion "p'" since there is no sample information, nor any previous information is known, you have to consider it as the "worse case scenario" and use the value of p'= 0.50

d= 0.04

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She has to take a sample of 1045 people to estimate the population proportion of her supporters with a confidence level of 99% and a margin of error of 4%

I hope this helps!

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2 years ago

at a basketball game, 6 adults pay $20 each and 4 children pay $10 each. What is the total cost for the adult tickets?​

at a basketball game, 6 adults pay $20 each and 4 children pay $10 each. What is the total cost for the adult tickets?