<h3>Given</h3>
z = 3
2y +z = 1
2x +3y +2z = 13
<h3>Find</h3>
x, y, z
<h3>Solution</h3>
... z = 3 is given
Substitute that into the second equation.
... 2y + 3 = 1
... 2y = -2 . . . . . subtract 3
... y = -1 . . . . . . . divide by the coefficient of y
Substitute these two solutions into the third equation.
... 2x +3(-1) +2(3) = 13
... 2x = 10 . . . . . . . . . . . . collect terms, subtract 3
... x = 5 . . . . . . . . . . . . . . divide by the coefficient of x
The variable values are: x = 5, y = -1, z = 3
Answer:
C I think
Step-by-step explanation:
C I think
if it Is correct give me brainliest
Answer:0
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0
Step-by-step explanation:
Substitute the number 21 for all the letter d's:
(21-10) + (21/3) = ?
11 + 7 = 18