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fiasKO [112]
3 years ago
7

The sum of four consecutive integers is 418. Find them.

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer: 103, 104, 105, and 106

Step-by-step explanation: This problem states that the sum of 4 consecutive integers is 418 and it asks us to find the integers.

First represent your 4 consecutive integers as follows.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

X + 3 ⇒ fourth integer

Since their sum is 418, our equation reads

x + (x + 1) + (x + 2) + (x + 3) = 418.

Simplifying on the left side we get 4x + 6 = 418.

Now we can subtract 6 from both sides of the equation and we have

4x = 412.

Now just divide both sides by 4 and we find that <em>x = 103</em>.

Finally, make sure you list all your answers.

If <em>x</em> is 103, then <em>x </em>+ 1 is 104, <em>x</em> + 2 is 105, and <em>x</em> + 3 is 106

Therefore, our 3 consecutive integers are 103, 104, 105, and 106.

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