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fiasKO [112]
3 years ago
7

The sum of four consecutive integers is 418. Find them.

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer: 103, 104, 105, and 106

Step-by-step explanation: This problem states that the sum of 4 consecutive integers is 418 and it asks us to find the integers.

First represent your 4 consecutive integers as follows.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

X + 3 ⇒ fourth integer

Since their sum is 418, our equation reads

x + (x + 1) + (x + 2) + (x + 3) = 418.

Simplifying on the left side we get 4x + 6 = 418.

Now we can subtract 6 from both sides of the equation and we have

4x = 412.

Now just divide both sides by 4 and we find that <em>x = 103</em>.

Finally, make sure you list all your answers.

If <em>x</em> is 103, then <em>x </em>+ 1 is 104, <em>x</em> + 2 is 105, and <em>x</em> + 3 is 106

Therefore, our 3 consecutive integers are 103, 104, 105, and 106.

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PLEASE HELP!!!! about solving systems!!! 30 points!!!
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Answer:

Step-by-step explanation:

<h2>d ) 13x−8y=28 11x−8y=24 </h2>

we can solve:

13x−8y=28

11x−8y=24

.............................(subtract side by side)

13x - 11 x + (-8y) - (-8y) = 28 - 24

2x + 0 = 4

x = 4/2 = 2 (divide both sides by 2),

then you replace x = 2 into 13x - 8y = 28, we have 26 - 8y = 28

or -8y = 28-26, or -8y = 2, then y = 2/ -8= -1/4

Solution x =2, y = - 1/4

b) 5x−2y=1 15x−3y=−3

5x−2y=1 (multiple bothe sides by 3)

15x−3y=−3

we have

15x−6y=3

15x−3y=−3

..................(  subtract side by side)

0 -3y = 6

y = 6/-3

y = -2

then you replace y =- 2 into 5x - 2y = 1, we have 5x + 4 = 1

or 5x = 1-4 or 5x = -3, then x = -3/5

Solution: x = -3/5, y = -2

c) 13x−12y=14 11x−4=18y

we have:

13x−12y=14

11x−4=18y

then:

13x−12y=14 ( multiple bothe sides by 6)

11x - 18y = 4   (multiple bothe sides by 4)

then

78x−72y=84

44x−72y= 16

...........................( subtract side by side)

34x = 68

or x = 68/34 = 2

then you replace x = 2 into 11x -4 = 18y , we have 22 -4 = 18y

or 18y = 18 or y = 18/18 = 1

Solution: x = 2 , y = 1

a) 12x−7y=2 4x−5y=6

we have

12x−7y=2

4x−5y=6  (multiple bothe sides by 3)

so

12x−7y=2

12x−15y=18

-------------------------(subtract side by side)

8y = -16

or y = -16/8 = -2

then you replace y = -2 into 4x -5y = 6 , we have 4x + 10 = 6

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Solution: x = - 1 , y = - 2

b) 7u+2v=1 17u+6v=−9

7u+2v=1   (multiple bothe sides by 3)

17u+6v=−9

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Solution: u = 3, v = - 10

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Solution: x= -4, y = - 1

Have a good day!

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