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PilotLPTM [1.2K]
3 years ago
5

PLEASE HELP QUICK!!! Six friends, four boys and two girls, went to a movie theater. They wanted to sit in a way so no girl sits

on either first or last chair. How many such arrangements are possible?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0

Answer:

I think the answer is 6

Step-by-step explanation:

B = Boy

G = Girl

B G G B B B

B G B G B B

B G B B G B

B B G G B B

B B G B G B  

B B B G G B

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What are benchmarks when using rounding?
cricket20 [7]

Answer:

Benchmark can be defined as the standard or reference point against which something can be measured, compared, or assessed.

Step-by-step explanation:

7 0
3 years ago
A taxi charges a fee, plus $1.80 per mile. how far can you go for $12?
EleoNora [17]

12: 1.8= 20/3. =>  the answer is 20/3 miles

7 0
3 years ago
What is the equation of a circle centered at the origin with radius 20?
Colt1911 [192]
We know that
the equation of a circle is
(x-h)²+(y-k)²=r²
where 
(h,k)-----> is the center
r--------> is the radius

is the center is the point (0,0) and radius  r=20
then
(h,k) is (0,0)

(x-0)²+(y-0)²=20²---------> (x)²+(y)²=400


the answer is
the option D.)  x2 + y2 = 400
3 0
2 years ago
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
2 years ago
Please help me!!!!! I need help!!!!!!!!!
Alex
The answer is 145 divided by tan 65 degrees.

Since the equation for tangent is opposite/adjacent, you can just plug the numbers in.

tan(65)=145/x (x being the height that you are trying to find)

tan(65) * x = 145

Then divide tan(65) to isolate the x and you get:

145/tan(65)

Hope this helps!
6 0
3 years ago
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