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DochEvi [55]
3 years ago
9

If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0?

Mathematics
1 answer:
Kay [80]3 years ago
6 0

(f – g)(x) = 0

16x-30 -(14x-6) =0

distribute

16x-30 -14x+6 = 0

combine like terms

2x-24=0

add 24 to each side

2x=24

divide by 2

x=12

Answer: x=12


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A triangular pyramid has a base with an area of 43 cm squared and lateral faces with bases of 10 cm and heights of 8.6 cm. What
Jet001 [13]

Answer:

The total surface area of triangular pyramid is 172 cm squared

Step-by-step explanation:

Triangular pyramid:

  • Number of faces 4.
  • Number of vertices of a triangular pyramid is 6.
  • The volume  is \frac13 AH. A= area of the pyramid's base and H= height of the pyramid.
  • The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.

Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.

The 3 sides of the triangular pyramid is triangle in shape.

The area of triangle is \frac12 \times base \times height.

The lateral surface area of the triangular pyramid is

=3(\frac12 \times base \times height)

=3(\frac12\times 10\times8.6) cm squared

=129 cm squared

The total surface area of triangular pyramid is

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=(43+129) cm squared

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8 0
3 years ago
Find the area A of the polygon with the given vertices.
Natalija [7]

Answer:

A = 35 square units

Step-by-step explanation:

Formula to calculate the distance between two points (x_1,y_1) and (x_2,y_2) is,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of the segment between A(2, 2) and B(9, 2) = \sqrt{(9-2)^2+(2-2)^2}

                                                                                     = 7 units

Length of the segment between B(9, 2) and C(9, -3) = \sqrt{(9-9)^2+(2+3)^2}

                                                                                       = 5 units

Length of the segment between C(9, -3) and D(2, -3) = \sqrt{(9-2)^2+(-3+3)^2}

                                                                                        = 7 units

Length of the segment between A(2, 2) and D(2, -3) = \sqrt{(2-2)^2+(2+3)^2}

                                                                                       = 5 units

Therefore, given polygon is a rectangle.

Area of the rectangle = length × width

                                    = 7 × 5

                                    = 35 square units

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A  quadrilateral always has one pair of parallel sides.
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