Hope this helps but if you got any other questions feel free to ask :) cause I suckeeeeddd at Geometry but I had to pass lolllll
Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is
. A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is
.
The lateral surface area of the triangular pyramid is

cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared
Answer:
A = 35 square units
Step-by-step explanation:
Formula to calculate the distance between two points
and
is,
d = 
Length of the segment between A(2, 2) and B(9, 2) =
= 7 units
Length of the segment between B(9, 2) and C(9, -3) = 
= 5 units
Length of the segment between C(9, -3) and D(2, -3) = 
= 7 units
Length of the segment between A(2, 2) and D(2, -3) = 
= 5 units
Therefore, given polygon is a rectangle.
Area of the rectangle = length × width
= 7 × 5
= 35 square units
A quadrilateral always has one pair of parallel sides.