<span>In the presence of oxygen, one glucose molecule has the energy to make up to 38 ATP. The ATP production is determined by the following steps, (-2 ATP) glycolysis preparatory phase, (7-9 ATP) glycolysis pay-off phase, (5 ATP) oxidative decarboxylation of pyruvate and (20 ATP) Krebs cycle. One glucose which has 38 ATP hence was the summation of all the process mentioned that took place. All these process take place under the cellular function of cellular respiration.<span>
</span></span>
An active site is a region that is present on an enzyme where the reactants or the substrate molecules we can say bind and experience a chemical reaction. The substrate is basically a reactant whose concentration is changing and that is converting into a product after binding at the active site of an enzyme
Hello. This question is incomplete. The full question is:
"You determine that you have only 3 copies left of an important DNA fragment, so you decide to amplify it. Using flanking primers, how many PCR cycles would you have to run to generate over one billion (10^9) copies of the fragment?
"
Answer:
Approximately 29 cycles of PCR would be required.
Explanation:
As you may already know, PCR is a technique used in molecular biology that allows part of a DNA molecule to be recycled into millions of copies.
PCR allows this replication to be done through cycles. Each PCR cycle lasts about 2 minutes and allows the DNA molecule to undergo the separation of the strands, the binding of the primers and the synthesis of new DNA strands through DNA polymerase. This cycle is usually repeated 32 times, but this number may change depending on the number of copies the researcher thinks is necessary.
In this case, if a researcher wants 10 ^ 9 copies of DNA, he must do the following calculation to find the number of PCR cycles needed:
32 ^ x = 10 ^ 9
x = 28.3 = approximately 29 cycles.
Answer:
The independent variable is the underlying conditions (x-axis) and the dependent variable is the percentages (y-axis)