Please help!! I did the table already but need the questions still!!

Suppose ABCD is a convex quadrilateral. Points M and N are midpoints of sides BC and AD, respectively. The area of the quadrilat

Katena32 [7]

Answer:

12 unit²

Step-by-step explanation:

area ΔAMC = 1/2 CM x AH' = 1/4 BC x AH'

area ΔABM = 1/2 BM x AH' = 1/4 BC x AH'

area ΔAMC = area ΔABM

for the same calculation, we can prove

area ΔACN = area ΔDCN

area ΔAMC + area ΔACN = 6

area ΔABM + area ΔDCN = 6

ABCD = area ΔAMC + area ΔACN + area ΔABM + area ΔDCN = 6 = 6 = 12

7 0

3 years ago

A regular pentagon has an apothem measuring 20 cm and a perimeter of 145. 3 cm. A rectangular pentagon has an apothem measuring

Effectus [21]

The area of the pentagon is 1,453 squared centimeters.

Given information-

The length of the apothem of a regular pentagon is 20 cm.

The measure of the perimeter of a regular pentagon is 145.3 cm.

The length of the apothem of a rectangular pentagon is 20 cm.

The measure of the perimeter of a rectangular pentagon is 145.3 cm.

<h3>Pentagon-</h3>

Pentagon is the closed shaped polygon which has 5 sides. When these 5 sides are equal in length then the pentagon is called teh regular pentagon. When four of the sides of pentagon make a rectangle then the pentagon is called the rectangular pentagon.

<h3>Area of regular pentagon-</h3>

Area of regular pentagon is half of the product of its apothem and perimeter. It can be given as,

$A=\dfrac{1}{2} \times 20\times 145.3\\A=1453$

Thus the area of the pentagon is 1,453 squared centimeters.

Learn more about the regular pentagon here;

brainly.com/question/858867

4 0

3 years ago

Four brothers have ages which are consecutive even integers. If the product of the ages of the two middle brothers is 528, how o

exis [7]

Answer:

The oldest brother is of age $26$ years.

Step-by-step explanation:

As the age of four brothers are consecutive even integers.

We assume that the ages are $x,(x+2),(x+4),(x+6)$ as their respective ages.

And the age of the youngest brother $x$ yrs.

Age of the oldest brother $(x+6)$ yrs.

According to the question

Product of two middle brother that is $(x+2)(x+4) =528$

So we will arrange this in our equation and solve the quadratic.

$(x+2)(x+4) =528$

$x^{2}+4(x)+2(x)+8 =528$

$x^{2}+4(x)+2(x)+8-528=0$

$x^{2}+6(x)-520=0$

Solving the quadratic by using middle term splitting or directly with quadratic formula we can find the value of 'x' .

Here it is solved with quadratic formula:

Comparing with standard equation $ax^{2}+b(x)+c=0$ ,here $a=1,b=6\ and\ c=-520$ .

$x= \frac{-b \pm \sqrt{b^2-4ac} }{2a} = \frac{-6 \pm \sqrt{6^2-4\times \ (-520)} }{2\times 1}$

$x=20,-26$

We will work with the positive value of (x) so the the age of the youngest brother $=(x)=20$ yrs.

And the age of the the oldest brother $=(x+6)=(20+6)=26$ years.

The age difference is of $(26-20)=6$ years.

4 0

4 years ago

Which of the following sets of numbers could represent the three sides of a right

Kamila [148]

The answer is either the first or second if u can put 2 down then both

8 0

3 years ago

Read 2 more answers

For what real values of $c$ is $x^2 - 8x + c$ the square of a binomial?

nikklg [1K]

Value of c is 16 for which equation $f(x) = x^2-8x+c$ is a square of binomial !

<u>Step-by-step explanation:</u>

Here we meed to find the value of c for which equation f(x) = x^2-8x+c or , $f(x) = x^2-8x+c$ is a square of a binomial . Let's find out:

We know that

⇒ $(x-a)^2 = x^2-2(a)(x)+a^2$ ..........(1)

Let's simplify given equation in question

⇒ $f(x) = x^2-8x+c$

⇒ $f(x) = x^2-2(4)x+c$

Comparing this equation with (1) we get :

$a=4 , c=a^2$

⇒ $c=a^2$

⇒ $c=4^2$

⇒ $c=16$

Therefore , Value of c is 16 for which equation $f(x) = x^2-8x+c$ is a square of binomial !

5 0

3 years ago

Please help!! I did the table already but need the questions still!!​

Please help!! I did the table already but need the questions still!!