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anyanavicka [17]
3 years ago
14

What is 7/8 x c for c=8

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

Value is 7

Step-by-step explanation:

We are given the expression, \frac{7}{8}\times c.

It is required to evaluate the expression for c= 8.

So, after substituting the value of c= 8 in the given expression, we get,

\frac{7}{8}\times c = \frac{7}{8}\times 8 = 7

Hence, the value of the expression at c= 8 is 7.

Mademuasel [1]3 years ago
6 0
<span><u><em>Answer:</em></u>
7

<u><em>Explanation:</em></u>
<u>We are given the equation:</u>
</span>\frac{7}{8}<span> * c

We want to get the value of the equation at <u>c = 8</u>.
Therefore, all we have to do is <u>substitute c in the equation with 8 and solve</u> as follows:
</span>\frac{7}{8}<span> * 8

= </span>\frac{7*8}{8}
<span>
The 8 in the numerator will be cancelled out with the 8 in the denominator leaving us with only the <u>7 as a solution</u>

Hope this helps :)</span>
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Is 5/8 more than 11/20
alexdok [17]
5/8 is more than 11/20

If we find the lower common multiple of the denominators which is 160 then we can multiply the top numerators by the opposite denominators

5x20=100
11x8=88

We now have
\frac{100}{160}  and  \frac{88}{160}

The one on the left is simplified to 5/8 and the right is simplified to 11/20

5 0
3 years ago
Read 2 more answers
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
3 years ago
Can some one answer this Answer please?
solmaris [256]
Answer
40
Explanation
It’s 40 because if you do 20/3 x 2/2 you will get 40/6
3 0
3 years ago
29×5/6 how do you solve it
frutty [35]
Is the whole thing divided by 6 or just the 5?
7 0
3 years ago
Read 2 more answers
How to solve this problem?
cluponka [151]
have you tried 42 because it's a 90 degree triangle and 30+18+42 equals 90
7 0
3 years ago
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