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salantis [7]
3 years ago
9

What is 252 = 11n + 10

Mathematics
2 answers:
puteri [66]3 years ago
4 0

Subtract 10 from both sides

252 - 10 = 11n

Simplify 252 - 10 to 242

242 = 11n

Divide both sides by 11

242/11 = n

Simplify 242/11 to 22

22 = n

Switch sides

<u>n = 22</u>

xz_007 [3.2K]3 years ago
3 0

Answer:

n=22 or 252=11(22)+10

Step-by-step explanation: 252=11n+10. Start by attempting to isolate the varyable by subracting 10 from both sides--> 242=11n, divide by 11--> 22=n

PROOF 252=11*22+10=242+10=252


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a)

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//

b) Proof:

We want to show ac \equiv bd (mod n).

So we have the two equations:

a-b=kn and c-d=mn and we want to show for some integer r that we have

(ac)-(bd)=tn. If we do that we would have shown that ac \equiv bd (mod n).

If a-b=kn, then a=b+kn.

If c-d=mn, then c=d+mn.

ac-bd  =  (b+kn)(d+mn)-bd

          =    bd+bmn+dkn+kmn^2-bd

          =           bmn+dkn+kmn^2

          =            n(bm+dk+kmn)

So the integer t such that (ac)-(bd)=tn is bm+dk+kmn.  

Therefore, ac \equiv bd (mod n).

//

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