Can someone explain this for me ? :)

Mathematics

1 answer:

ruslelena [56]2 years ago

7 0

34! Find the area of each of the six sides and then add them up:)

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Austin Family Furniture purchases recliners directly from the manufacturer for $235.00 each. The recliners are marked up 185% of

Elina [12.6K]

235 times 1.85= 434.75
434.75+ 235=669.75

3 0

2 years ago

Given that tan? Tan^2 0=3/8 what is the value of sec 0?

Ronch [10]

Answer:

1.068.

Step-by-step explanation:

Use the identity

sec^2 O = 1 + tan^2 O

= 1 + (3/8)^2

= 1 9/64

= 73/64

so sec O = √73/8

= 1 .068.

7 0

3 years ago

Help please stuck again .

xenn [34]

If the polygons are similar, then the top side is equal to one half of the left side.
Since side (x -1) = 8, then x = 9.

3 0

2 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

2 years ago

PLZ HELP ME YOU WILL GET GOOD KARMA PLZZZZZZ

lesya692 [45]

Answer:

I recommend trying this it explains how to do it and gives you the answer

6 0

3 years ago