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NikAS [45]
3 years ago
12

The function f(x) is given by the set of ordered pairs.

Mathematics
1 answer:
viva [34]3 years ago
4 0

Answer: f(-6) = 10.

Step-by-step explanation: This above equation is the only one that contains both coordinates of one of the ordered pairs in the correct order, so it is the answer.

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7 watermelons cost $8.96.Which equation would help determine the cost of the 5 watermelons? Into two fractions with a expontnet
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Answer:

hola CTM

Step-by-step explanation:

4 0
3 years ago
Please Find the distance between the two points rounding to the nearest tenth (if necessary).
Sphinxa [80]

Answer:

10.29 u

Step-by-step explanation:

<u>Given :- </u>

  • Two points (7,4) and (-2,9) is given to us.

And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,

:\implies D = √{(x2-x1)² + (y2-y1)²}

:\implies D =√[ (7+2)² +(9-4)²]

:\implies D =√[ 9² +5²]

:\implies D =√[ 81 +25]

:\implies D = 10.29

<h3>Hence the distance between the two points is 10.29 units .</h3>
8 0
3 years ago
Read 2 more answers
Use greatest common factor and the distributive property to write an equivalent expression in factored form for the following Ex
aksik [14]
To solve this find the common number that can be divided by both and use that number.

In this case, 4 is divisible by both 4 and 12, and thus the final expression would be

4(d + 3e).

8 0
3 years ago
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The original price of a barbecue grill is $79.50 the girl is markdown 15% what is the sale price of the grill
riadik2000 [5.3K]
The sale or discounted Price: $67.57
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6 0
3 years ago
Please please help me
Alex73 [517]

Answer:

x = 5.5

Step-by-step explanation:

Given 2 secants intersecting the circle from a point outside the circle then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 14) = 6(6 + 12)

x² + 14x = 6 × 18 = 108 ( subtract 108 from both sides )

x² + 14x - 108 = 0 ← in standard form

with a = 1, b = 14 and c = - 108

Using the quadratic formula to solve for x

x = ( - b ± \sqrt{b^2-4ac} ) / 2a

  = ( - 14 ± \sqrt{14^2-(4(1)(-108)} ) / 2

  = ( - 14 ± \sqrt{196+432} ) / 2

  = ( - 14 ± \sqrt{628} ) / 2

  x = \frac{-14-\sqrt{628} }{2} or x = \frac{-14+\sqrt{628} }{2}

  x = - 19.5 or x = 5.5 ( to 1 dec. place )

However x > 0 ⇒ x = 5.5

6 0
3 years ago
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