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Kaylis [27]
3 years ago
7

Evaluate 3^−1⋅(4⋅6)⋅2^−3

Mathematics
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

3^{-1}*(4*6)*2^{-3}=1

Step-by-step explanation:

3^{-1}*(4*6)*2^{-3}

\frac{1}{3}*24*\frac{1}{8}

\frac{1}{3}*3

1

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3/5n+15=10+2/5n what is n
Nutka1998 [239]

\textsf{Hey there!}

\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}

\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}

\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}

\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}

\textsf{Solve\ the set we have left over}

\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}

\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}

\mathsf{\dfrac{1}{5}n+15-15=10-15}

\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }

\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }

\mathsf{10-15=-5}

\mathsf{New\ equation: \dfrac{1}{5}n=-5}

\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}

\mathsf{\dfrac{1}{5}n\times5=5\times-5}

\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \  it \ gives \ us \ 1}\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}

\mathsf{n =5\times-5}\\\mathsf{5\times-5 = -25}

\textsf{Thus, \underline{\bf{n = -25}}}\checkmark

\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\bf{n =-25}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

7 0
3 years ago
Input-Output<br> 3 27<br> 8 72<br> 9 81<br> 5 45<br> 4 <br> what is the answer for the 4 number?
Mkey [24]

Answer:

Try 36

Step-by-step explanation:

5 0
3 years ago
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A ticket costs £656<br> Last year it cost £640<br> What percentage increase is this ?
evablogger [386]

Answer:

2.5%

Step-by-step explanation:

656 / 640 = 1.025

1.025 into percent is 102.5%

102.5% - 100% = 2.5

640 + 2.5% of 640 = 656

BOOM

3 0
2 years ago
There are exactly four positive integers n such that (n +7) is a factor of ( n +1) . Find the largest such n .
kipiarov [429]
\dfrac{n+1}{n+7}=\dfrac{n+7-6}{n+7}=1-\dfrac6{n+7}

n+7 will be a factor whenever the remainder term -\dfrac6{n+7} vanishes. But this will never happen for any integer n, so I suspect the question is inaccurately posed. Are there some characters missing?
4 0
4 years ago
−7x−12=−61 what is x
oee [108]

Answer:

X = 7

Step-by-step explanation:

6 0
3 years ago
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