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madreJ [45]
3 years ago
5

I NEED HELP ASAP LIKE NOWWW

Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

C / (2pi) = r;  r= 13.9 cm

2A/b = h   ;  h= 5

Step-by-step explanation:

The formula for the circumference of a circle is  C = 2* pi * r.

Solving for r, we need to divide by 2 * pi on each side

C/(2* pi) = 2*pi*r/ (2* pi)

C / (2pi) = r

If the circumference is 87, we can find r by substituting into the equation.

87 / (2 * 3.14) = r

87/ 6.28 = r

13.85350318=r

Rounding to the nearest tenth

r= 13.9 cm


The formula for the area of a triangle is  A = bℎ /2  

To solve the formula for h, we need to multiply each side by 2

2*A = bh

Then divide each side by b

2A/b = bh/b

2A/b = h


If the  area  of a triangle is 25  and the base of 10 , we can substitute in to find the height.

2* 25 /10 = h

50/10 = h

5 =h

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Answer: the answer is 1679616

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Enter the values for the highlighted variables to complete the steps to find the sum: (see picture)
dangina [55]

Answer:

a = -1

b = -9

c = 9

d = 3

e = 3

f = 2

g = 3/2

Step-by-step explanation:

* Lets explain how to solve the problem

∵ \frac{3x}{2x-6}+\frac{9}{6-2x} are rational fractions

- To add or subtract the rational fractions they must have same

  denominator

∵ 6 - 2x must be written 2x - 6, take (-1) as a common factor from 6 - 2x

∴ - 1(-6 + 2x) = - 1(2x - 6)

∴ \frac{3x}{2x - 6}+\frac{9}{6-2x}=\frac{3x}{2x-6}+\frac{9}{-1(2x-6)}

∴ a = -1

∵ 9 ÷ -1 = -9

∴ =  \frac{3x}{2x-6}+\frac{-9}{2x-6}

∴ b = -9

∵ The denominators of the two fractions are 2x - 6

∴ We can add them by adding their numerator

∵ 3x + -9 = 3x - 9

∴ = \frac{3x-9}{2x-6}

∴ c = 9

∵ 3x - 9 has a common factor 3

∴ 3x - 9 = 3(x - 3)

∵ 2x - 6 has common factor 2

∴ 2x - 6 = 2(x - 3)

∴ = \frac{3(x-3)}{2(x-3)}

∴ d = 3 , e = 3 , f = 2

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∴ = \frac{3}{2}

∴ g = 3/2

5 0
3 years ago
Which of the following functions represent exponential decay?
Zina [86]

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ is the function that represent exponential decay.

Explanation:

The exponential decay can be represented by

$f(x)=a \cdot b^{x}$ where a>0 and 0

Option A: $f(x)=3(1.7)^{x-2}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{x-2}$ does not represent exponential decay.

Hence, Option A is not the correct answer.

Option B: $f(x)=3(1.7)^{-2 x}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{-2 x}$ does not represent exponential decay.

Hence, Option B is not the correct answer.

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$

From the function, we can see that a=3^5=243 and b=\frac{1}{3} =0.3333

Thus, a>0 and 0

Thus, the function $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ represent exponential decay.

Hence, Option C is the correct answer.

Option D: $f(x)=3^{5}(2)^{-x}$

From the function, we can see that a=3^5=243 and b=2

Thus, a>0 and b>1

Thus, the function $f(x)=3^{5}(2)^{-x}$ does not represent exponential decay.

Hence, Option D is not the correct answer.

8 0
4 years ago
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Mice21 [21]
It’s 38 :) I hope it helps
8 0
3 years ago
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Thank you to whoever helps
MakcuM [25]
The answer is C because x2 is a parabola
5 0
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