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kondor19780726 [428]
3 years ago
14

When did the silent movie era end? A.1919 B.1929 C.1939 D.1949

Computers and Technology
2 answers:
Tomtit [17]3 years ago
7 0
Pretty sure your answer is B. 1929
11111nata11111 [884]3 years ago
5 0

Answer:

The answer is 1929.

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Advocard [28]
Lacking a response to my question, I'll assume there's no "correct' answer here. 

Joaquin could contact the university's graphic arts department, or if he's interested in the programming side of it, the computer science department, and ask if they have any information on the topic. If he's already majoring to become an animator, then he should talk to one of his professors to see if they know someone in the business that would speak with Joaquin. 

The faster and better way would be to go to reddit, or some site at which animators congregate (most probably found through Google), read the forums, and create if he's not finding a suitable answer.
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3 years ago
Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)
Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){  cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Class Participation: "; cin>>classp; </em>

<em> while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; } </em>

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Test: "; cin>>test; </em>

<em> while(test <0 || test > 100){  cout<<"Test: "; cin>>test; } </em>

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Assignment: "; cin>>assgn; </em>

<em> while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; } </em>

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Examination: "; cin>>exam; </em>

<em> while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; } </em>

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Practice Score: "; cin>>prctscore; </em>

<em> while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; } </em>

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

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3 years ago
What do you understand by storage devices ? Name any two storage devices.​
MatroZZZ [7]

Answer:

Types of storage devices

Primary Storage: Random Access Memory (RAM) Random Access Memory, or RAM, is the primary storage of a computer. ...

Secondary Storage: Hard Disk Drives (HDD) & Solid-State Drives (SSD) ...

Hard Disk Drives (HDD) ...

Solid-State Drives (SSD) ...

External HDDs and SSDs. ...

Flash memory devices. ...

Optical Storage Devices. ...

Floppy Disks.

6 0
3 years ago
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Sati [7]

Answer:

         n = f = 7

loop  f = gt(n,1) f * (n = n - 1) :s(loop)

         output =  f

end

Explanation:

3 0
3 years ago
According to which virtue do you need to secure information by limiting computer access to authorized personnel only ?
nadya68 [22]

Confidentiality is a virtue which we need to secure information by limiting computer access to authorized personnel only. People trust us to keep their private matters private. Keeping that confidence is an important aspect of trust.  

8 0
3 years ago
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