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BaLLatris [955]
4 years ago
5

The length of a banquet table is 4 feet longer than 6 times its width. If the perimeter is 78 feet, what are the dimensions of t

he table?
Mathematics
1 answer:
harina [27]4 years ago
7 0
Hello,
2(l+w)=78
Divided 2 from both side
2(l+w)/2=78/2
l+w=39 feet

l=6w+4
Replace l with 6w+4

6w+4+w=39
7w+4=39
Subtract 4 from both side
7w=35
Divided 7 from both side
w=5 feet
l=6w+4
l=6(5)+4
l=30+4
l=34 feet. As a result, the length of the rectangle is 34 feet and the width of rectangle is 5 feet. Hope it help!
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Side AD is 4 times the length of corresponding side EH, so we expect side AB to be 4 times the length of side EF.

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Then, we have the following rounding rule:

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