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BaLLatris [955]
3 years ago
5

The length of a banquet table is 4 feet longer than 6 times its width. If the perimeter is 78 feet, what are the dimensions of t

he table?
Mathematics
1 answer:
harina [27]3 years ago
7 0
Hello,
2(l+w)=78
Divided 2 from both side
2(l+w)/2=78/2
l+w=39 feet

l=6w+4
Replace l with 6w+4

6w+4+w=39
7w+4=39
Subtract 4 from both side
7w=35
Divided 7 from both side
w=5 feet
l=6w+4
l=6(5)+4
l=30+4
l=34 feet. As a result, the length of the rectangle is 34 feet and the width of rectangle is 5 feet. Hope it help!
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1- question

Data:
width = 6 cm
length = 5 cm
height = 8 cm


<span>First we will find the area of ​​the base that is square, we have:
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Ab = 6 * 5 
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<span>Now we will calculate the volume of a square pyramid, we have:
</span>Formula: V =  \frac{1}{3}  A_{b}  *h

Solving:
V = \frac{1}{3} A_{b} *h
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\boxed{\boxed{V = 80\:cm^3}}\end{array}}\qquad\quad\checkmark

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2- question:

Data:
width = 7 in
length = 7 in
height = 9 in


First we will find the area of ​​the base that is square, we have:

Ab = 7 * 7 
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Now we will calculate the volume of a square pyramid, we have:
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Solving:
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Answer: 
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