Assuming 5 is the base. I'm going to leave that out for now.
2log(5x^3) + (1/3)log(x^2+6)
power rule
log(5^2 x^3*2) + log((x^2 + 6)^(1/3))
log(25x^6) + log((x^2 + 6)^(1/3))
quotient rule
log(25x^6 / (x^2 + 6)^(1/3))
Answer:
Accelerating to top speed, deaccelerating to finish line.
Step-by-step explanation:
If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:
This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.
Answer:
0.35865 and 0.35867
Step-by-step explanation:
for this number, the hundreths thousandths place is
0.358659 (bolded)
so, since the 9 rounds up, the estimated number would be 0.35866
the numbers before would be 0.35865 and after, 0.35867
Answer:
(1252+252)(52−1)
=(1252+252)(52+−1)
=(1252)(52)+(1252)(−1)+(252)(52)+(252)(−1)
=390625−15625+15625−625
=390000
divide by 39 is
=10000
Answer:
ghcfhfdh
Step-by-step explanation: