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nadya68 [22]
2 years ago
12

Jace owns twice as many dvds an Louis. Bo has sixty fewer dvds than 5 times louis's collection. If jace and bo have the same amo

unt of dvds how many dvds are in louis's collection
Mathematics
1 answer:
Yuki888 [10]2 years ago
3 0

Answer: Jace owns 20 dvds

Step-by-step explanation:

Let x represent the number of DVDs that Louis owns.

Jace owns twice as many dvds an Louis. This means that the number of DVDs that Jace owns is 2x.

Bo has sixty fewer dvds than 5 times louis's collection. This means that the number of DVDs that Bo owns is 5x - 60

If jace and bo have the same amount of dvds, it means that

5x - 60 = 2x

5x - 2x = 60

3x = 60

Dividing both sides by 3, it become

x = 60/3

x = 20

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kirill115 [55]

The standard form of a line: Ax+By=C.

The point-slope form: y-y_1=m(x-x_1)

We have the point (3, -1) and the slope m = -1. Substitute:

y-(-1)=-1(x-3)

y+1=-x+3                    <em>add x to both sides</em>

x+y+1=3             <em>subtract 1 from both sides</em>

\boxed{x+y=2}

5 0
3 years ago
Cal is measuring temperature changes in four substances over different time periods as part of a school project. Which data show
djyliett [7]

Answer:

C) The third table. K= 5

C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5

Step-by-step explanation:

1) Below there are the missing data:

A proportional relationship through a constant k. It is obtained when we divide:

k=\frac{y}{x}

2)In this case, when we divide the temperature (T) by the time (h).

k=\frac{T}{h}

3)So, examining the table below we are searching for a ratio k common to all measures (temperatures over hour).

A) \frac{12}{3}\neq\frac{25}{5}\neq\frac{36}{6}\neq\frac{81}{9}\\B) \frac{22.5}{3}\neq\frac{30}{4}\neq\frac{52.5}{7}\neq\frac{67.5}{8}\\C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5\\D)\frac{8.5}{2}\neq\frac{22.5}{5}\neq\frac{28.5}{7}\neq\frac{36}{8}

3 0
3 years ago
Solve by substitution y=x+4, y=2x+5
Amiraneli [1.4K]
X+4=2x+5
-1=x
hope this helps
4 0
2 years ago
Can you help me to solve this<br>​
RUDIKE [14]

Answer:

Is the question even complete ?

Step-by-step explanation:

5 0
1 year ago
A certain virus is dying off at a rate of 18% per hour. Initially there were
djyliett [7]

Answer:

3 strain would still alive after 48 hours

Step-by-step explanation:

Initial population of virus = 40000 grams

A certain virus is dying off at a rate of 18% per hour.

We are supposed to find  how much of the  strain would still be alive after 48 hours

Formula : N(t)=N_0(1-r)^t

N_0=Initial population

N(t)= Population after t hours

r = rate of decrease = 18% = 0.18

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So,the  strain would still be alive after 48 hours=40000(1-0.18)^{48}=2.91 \sim 3

Hence 3 strain would still alive after 48 hours

3 0
3 years ago
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