Answer:
(2y-cubert(15)x)(4y^2+2cubert(15)xy+cubert(15^2)x^2)
Step-by-step explanation:
It almost look like someone possibly meant to write a perfect cube there instead of 51... but we can still factorize this... it just won't be as pretty.
The formula for factoring a difference of cubes is
u^3-v^3
=(u-v)(u^2+uv+v^2).
So the answer here is
(2y)^3-(cubert(15)x)^3
=(2y-cubert(15)x)(4y^2+2cubert(15)xy+cubert(15^2)x^2)
cubert means cube root of
The thing I'm cube rooting is the thing in ( ) next to the cubert.
Make sure you actually write the symbol for cube root instead of my notation.
