All equilateral triangles are isosceles? A. True B. False

Mathematics

2 answers:

mojhsa [17]3 years ago

8 0

Answer:

Yes, all equilateral triangles are also isosceles.

Step-by-step explanation:

An isosceles triangle has at least two sides of the triangle of equal measure and the two base angles are equal in degree measure. By definition all sides of an equilateral triangle are equal in length and all angles are equal in degree measure.

Using this info, I will say yes, all equilateral triangles are also isosceles. The correct answer would be A.) True.

Maru [420]3 years ago

7 0

Answer:

A. true

Step-by-step explanation:

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a rectangular mural measures 3.5ft by 5.5ft. Rosalie creates a new mural that is 1.5 ft longer. What is the perimeter of Rosalie

saveliy_v [14]

Answer:

P = length + width x 2
P = 3.5ft + 5.5ft x 2
P = 9ft x 2
P = 18ft + 1.5ft (the new mural)
P = 19.5ft

Therefore the perimeter of Rosalie's new mural is 19.5ft

6 0

2 years ago

F(x)=x^3+3

lawyer [7]

Answer:

(a) -3/4

(b) -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

evaluating the function at the midpoint of the bracketing interval
choosing a smaller bracketing interval
identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

See the attached table for function values.

_____

Comment on bisection iteration

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.