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RoseWind [281]
3 years ago
15

At 2:00pm a car's speedometer reads 20mph, and at 2:10pm it reads 30mph.

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Over this 10-minute interval, the car's average acceleration is

\dfrac{30\,\mathrm{mph}-20\,\mathrm{mph}}{10\,\mathrm{min}}=\dfrac{10\,\mathrm{mph}}{\frac16\,\mathrm h}=60\dfrac{\rm mi}{\mathrm h^2}

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.

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Marissa bought 2 and a half gallons of orange juice to make punch how many quarts of orange juice did. Marissa buy
Nookie1986 [14]
The answer is as follows:
There are 2 pints in a quart. 
There are 2 quarts in a half gallon.
There are 2 half gallons in a gallon.
Therefore, we can conclude that there are 10 quarts of orange juice.
7 0
3 years ago
Help with this question ??
NNADVOKAT [17]

Answer: 12 tables minimum, 15 max.

Step-by-step explanation:

If you substitute 14 in an inequality

200c + 500t >= 8800

200(14) + 500t and solve for t, you get t must be at least 12.

C +T cannot exceed 29

So figure 14 +12 =26 so they could sell up to 15 tables and not go over 29.

You will have to enter the t values 12,13,14,15

5 0
3 years ago
The density of ethanol is around 0.8g/mL. What is the mass of 20mL of ethanol?
Harman [31]

Answer: 0.7893g//mL

If 20 mL of ethanol (density =0.7893g//mL) is mixed with 40mL water (density = 0.9971g//mL)

Step-by-step explanation:

4 0
3 years ago
7. Sarah bought a lawnmower for $320. She signed up for the buy now pay later plan at the store with the following conditions: $
erastova [34]
Amount financed
320−100=220

Total paid
100+25×12=400

Interest paid
400−320=80

Interest rate=(2yc)÷(m (n+1))
I=(2×12×80)÷(220 (12+1))
I=(2×12×80)÷(220×13)
I=0.67×100
I=67%
4 0
3 years ago
Read 2 more answers
What is b1 and r of geometrical sequence if b3 −b1 = 16 and b5 −b3 = 144.
Naily [24]

Answer:

b1 = 2 ; r = 3

Step-by-step explanation:

Given that :

if b3 −b1 = 16 and b5 −b3 = 144.

For a geometric series :

Ist term = a

Second term = ar

3rd term = ar^2

4th term = ar^3

5th term = ar^4 ;...

If b3 - b1 = 16;

ar^2 - a = 16

a(r^2 - 1) = 16 - - - (1)

b5 - b3 = 144

ar^4 - ar^2 = 144

ar^2(r^2 - 1) = 144 - - - - (2)

Divide (1) by (2)

a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144

a / ar^2 = 1 / 9

ar^2 = 9a

Substitute for a in ar^2 - a = 16

9a - a = 16

8a = 16

a = 2

From ar^2 - a = 16

2r^2 - 2 = 16

2r^2 = 16 + 2

2r^2 = 18

r^2 = 18 / 2

r^2 = 9

r = √9

r = 3

Hence ;

a = b1 = 2 ; r = 3

7 0
3 years ago
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