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Evgen [1.6K]
3 years ago
11

Marginal utility is the: select one:

Business
1 answer:
garri49 [273]3 years ago
3 0

Marginal utility is the <u>"change in total utility obtained by consuming one more unit of a good".</u>

Marginal utility evaluates the additional satisfaction a customer earns from consuming extra units of products or services. The idea of marginal utility is utilized by economists to decide the amount of a thing buyers are happy to buy. Positive peripheral utility happens when the utilization of an extra thing builds the total utility, while negative marginal utility occurs when the utilization of an extra thing diminishes the total utility.  

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I think it’s around 18 million or more people that make more than 1 million or 1 million yearly
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True or false: apple computer, inc. collected information on the age of their customers. the youngest customer was 12 and the ol
vova2212 [387]
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3 0
3 years ago
Suppose that a company needs new equipment, and that the machinery in question earns the company revenue at a continuous rate of
julia-pushkina [17]

Answer:

a-The present value of revenue in the first year is $61,085.92.

b-The total time it would take to pay for its price is 2.44 years of 29.33 months.

Explanation:

a-

Let the function of the revenue earned is given as

S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt

Here

  • a and b are the limits of integral which are 0 and 1 respectively
  • r is the rate of interest which is 5% or 0.05
  • S(t) is the function of value which is S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225

    So the present value of revenue in the first year is $61,085.92.

    b-

    The time in which the machine pays for itself is given as

    PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt+\int\limits^t_1 {S(t)e^{-0.05t}} \, dt\\PV=61085.9225+\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt

    The present value is set equal to the value of machine which is given as

    $160,000 so the equation becomes:

    PV=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\160000=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt=160000-61085.9225\\\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt=98914.07\\\\t=-\dfrac{\ln \left(0.93034\right)}{0.05}\\t=1.44496

    So the total time it would take to pay for its price is 2.44 years of 29.33 months.

6 0
3 years ago
In addition to compensation, customers expect _____. in other words, they expect fairness in terms of policies, rules and timeli
konstantin123 [22]
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2 years ago
Kraven Corp. borrows $100,000 by signing on a 1-year, 8% promissory note from General Finance Company and assigns $120,000 of it
Aleks [24]

Answer and Explanation:

The journal entry is shown below:

Cash Dr $98,800

Finance charge Dr ($120,000 × 1%) $1,200

       To Liability - Financing Arrangement $100,000

(being receipts of cash is recorded)

Here cash and finance charge is debited as it increased the assets and expenses and liability is credited as it also increased the liabilities. Also, the cash & expenses contains normal debit balance and liabilities contains normal credit balance

6 0
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