The researcher wants to investigate whether carpet makes a difference in the mean bacterial concentration in air. the null and alternative hypotheses would be:
H0: The mean of the carpeted rooms = the mean of the uncarpeted rooms
Ha: The mean of the carpeted rooms ≠ the mean of the uncarpeted rooms
The attention of bacteria majorly depends on the awareness of inoculum, incubating temperature, and the metabolic country of inoculated pressure used. The bacterial concentration suspended in growth media may be calculated.
In idea, you could listen to cells through filtration or centrifugation, but likely no greater than a hundredfold. for your case, you're asking to concentrate by 10,000 fold. So you sincerely might want to develop denser cultures of cells. You can centrifuge your modern broth and resuspend the pallet in a clear broth.
In microbiology, the minimal inhibitory attention (MIC) is the lowest concentration of a chemical, generally a drug, which prevents the visible boom of a bacterium or bacteria.
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Answer:
The answer is B, both capital expenditure and dividends paid.
Explanation:
In the Statement os Cash Flow, cash provided by operating activities fails to take into account that a company must invest in a new property, plant, and equipment and must maintain dividends at current levels to satisfy investors.
Free cash flow describer the net cash provided by operating activities after adjusting for capital expenditures and dividens paid.
Answer:a.Total manufacturing costs for Job 313 =$52,500
Unit Product Cost for Job 313=$30
Explanation:
Total manufacturing costs=Direct materials+Direct labor costs+Overhead costs
But Overhead cost =115% of direct labor cost
= 115% x $10,600
=$12,190
Total manufacturing costs =$29,710 + $10,600+$12,190
=$52,500
Unit Product Cost=Total Manufacturing costs/ Total Number of Units Produced =$52,500 /1,750 units
=$30
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Answer:
This is not necessarily evidence that the proportion of Americans who are afraid to fly has decreaseddecreased because belowbelow 0.10 because the proportion of sample, is nothing very close to 0.10.
Explanation:
n = 1100
p = 0.10
Using the formula np(1-p), we will have
= 1100(0.10)*(1 - 0.10)
= 1100*0.10*0.90
= 99
99 ≥ 10
This satisfies normal distribution condition. That is, proportion of sample are normally distributed.