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evablogger [386]
3 years ago
5

A scientest is studying a new super bacteria that is threatening to cause an outbreak. On the first day, there were 5 organisms

present but on day two the scientest found that each of those organisms had split into 5 more. On the third day, it was discovered that each of the organisms from day two had split into 5 additional organisms. What is the population of bacteria on day 3? A.15 B. 50 C. 125 D. 105
Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

C. 125

Step-by-step explanation:

Given:

Bacteria on day 1 = 5

On day 2, each bacteria got split into 5.

So, number of bacteria on day 2 = 5\times 5 = 25

Now, again on day 3, each of the 25 bacteria got split into additional 5 bacteria.

So, number of of bacteria on day 3 = 25\times 5 =125

Therefore, the population of bacteria on day 3 is 125.

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The slope is -2 full equation is y = -2x -2

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Through:(3,-1),slope=-1
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y = -x + 2

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Use the point-slope formula y - k = m(x -h):

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4 years ago
Choose the correct simplification of the expression (-9a^3b^2c^10)^0
Flauer [41]

Option C: 1 is the simplification of the expression \left(-9 a^{3} b^{2} c^{10}\right)^{0}

Explanation:

The given expression is \left(-9 a^{3} b^{2} c^{10}\right)^{0}

We need to simplify the given expression.

<u>Simplification:</u>

To simplify the given expression, let us apply the exponent rule, a^{0}=1 where a \neq 0

Thus, the the exponent rule a^{0}=1 means that any value (except zero) to the power of zero is equal to one.

Thus, the expression \left(-9 a^{3} b^{2} c^{10}\right)^{0} becomes,

\left(-9 a^{3} b^{2} c^{10}\right)^{0}=1

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Hence, Option C is the correct answer.

8 0
3 years ago
What’s is part A?? .....
bixtya [17]

Answer:

A. 3

B. 4

C. 1

D. 2

Step-by-step explanation:

Consider all equations:

A. y=x^2 -6x+8

This is the equation of parabola with vertex at point

x_v=\dfrac{-b}{2a}=\dfrac{-(-6)}{2\cdot 1}=3\\ \\y_v=3^2-6\cdot 3+8=9-18+8=-1

The y-intercept is at point

x=0\\ \\y=0^2-6\cdot 0+8=8

Since

x^2 -6x+8=x^2-4x-2x+8=x(x-4)-2(x-4)=(x-2)(x-4),

the x-intercepts are at points (2,0) and (4,0)

The leading coefficient is 1 > 0, then the parabola opens upwards.

Hence, the graph of this parabola is 3.

B. y=(x-6)(x+8)

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is 1 > 0, then the parabola opens upwards.

The only possible choice is parabola 4.

C. y=(x-6)^2+8

This parabola has the vertex at point (6,8), opens upwards, therefore does not intersect the x-axis.

The graph of this parabola is 1.

D. y=-(x+8)(x-6)

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is -1 > 0, then the parabola opens downwards.

The only possible choice is parabola 2.

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