The surface area of the pyramid is 18,541 mm² . Option C
<h3>How to determine the surface area</h3>
The formula for surface area of a regular hexagonal prism is expressed as;
Where;
- a is the edge length = 44 millimeters
- h is the height = 95 millimeters
A = 2. 598 ( 44)² + 3(44)
Simplify
A = 5029. 728 + 132
Find the square root
A = 5029. 728 + 132(102. 357)
expand the bracket
A = 5029. 728 + 13511. 124
A = 18, 540. 85
A = 18,541 mm² in thee nearest square millimeter
Thus, the surface area of the pyramid is 18,541 mm² . Option C
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Answer to 4.
About 106.66
If they ask if a rounded answer it would be 107. You just divide 2560 by 24 because you know 24 balls is 3 pounds.
The answer is 5.2π in² = 16.3 in²
The area (A) of the circle with radius r is: A = r²π
It is known:
π = 3.14
t = 5
⇒
A = r²π = (16/7)²π = (2.28)²π = 5.2π = 5.2 · 3.14 = 16.3 in²
Its D. they are equidistant from the center of the circle , just took the test and that was the answer on apex