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damaskus [11]
3 years ago
14

If a die is rolled one time, what is the probability of getting a 4​

Mathematics
2 answers:
koban [17]3 years ago
8 0

Answer: 16.7%

Step-by-step explanation: To find the probability of rolling a 4 on a dice, remember that there are 6 possibilities of rolling a number.

One way to think about it is that it's certain that one of those six sides will land facing upwards which is a probability of 1 or 100%.

Since only one side can face upwards for a given role, we have to divide up that value among all the possibilities. Let's divide 1 by the number of sides on the dice.

1 ÷ 6 = 0.167 or 16.7%

This means that it would not be likely to role a 4, but it would be just as likely as rolling any other number.

Therefore, the probability of rolling a 4 is 16.7%.

BaLLatris [955]3 years ago
5 0

Answer:

1/6

Step-by-step explanation:

You have one die, with one 4 and six sides. The probability of getting a 4 with one roll is 1/6.

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Solve the equations<br>Y=2x-4, 3x+y=1​
liberstina [14]

Step-by-step explanation:

y = 2x - 4

3x + y = 1

y = 1 - 3x

Equating,

2x - 4 = 1 - 3x

2x + 3x =  1 + 4

5x = 5

x = 1

Placing it,

y = 1 - 3(  1)

y = 1 - 3

y =  - 2

6 0
3 years ago
For the given pair of equations, give the slopes of the lines, and then determine whether the two lines are parallel, perpendicu
Nat2105 [25]

Answer/Step-by-step explanation:

Given,

10x - 3y = 3

3x + 10y = 30

Rewrite both equation in slope-intercept form, y = mx + b.

Where, m = slope of the line.

Thus,

✔️10x - 3y = 3

-3y = -10x + 3

y = 10/3x - 1

Slope of this line would be 10/3

✔️3x + 10y = 30

10y = -3x + 30

y = -3/10x + 3

The slope of this line is -³/10.

✔️The two lines are pendivukar to each other because the slope of one is the negative reciprocal of the other.

4 0
3 years ago
Find EC help me please
kow [346]
Ok to find this answer you first have to subtract the 16 from the 30 to find what "CB" is, which is 14. From there subtract 14 and 16 from 49 to find that the whole answer is 35. I think that is the answer but I'm not positive.
5 0
3 years ago
In this problem, y = c1ex + c2eâx is a two-parameter family of solutions of the second-order DE y'' â y = 0. Find a solution of
SCORPION-xisa [38]

Answer:

y(t) = 2e^t -e^{-t}

Step-by-step explanation:

Assuming this complete problem: "In this problem,

y = c1ex + c2e−x

is a two-parameter family of solutions of the second-order DE

y'' − y = 0.

Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions.

y(0) = 1,    y'(0)= 3"

Solution to the problem

For this case we have a homogenous, linear differential equation with order 2, and with the general form:

ay'' +by' +cy=0

Where a =1, b=0, c=-1

And we can rewrite the differential equation in terms y = e^{rt} like this:

[e^{rt}]'' -e^{rt}=0

And applying the second derivate we got:

r^2 e^{rt} -e^{rt}=0

We can take common factor e^{rt} and we got:

e^{rt} (r^2-1) =0

And for this case the two only possibel solutions are r=1, r=-1

And the general solution for this case is given by:

y = c_1 e^{r_1 t} + c_2 e^{r_2 t}

Replacing the roots that we found we got:

y = c_1 e^{t} +c_2 e^{-t}

Now we can find the derivates for this last espression

y' = c_1 e^t -c_2 e^{-t}

y'' = c_1 e^t +c_2 e^{-t}

From the initial conditions we have this:

y(0)=1 =c_1 e^{0} +c_2 e^{-0}= c_1 +c_2   (1)

y'(0) =3= c_1 e^{0} -c_2e^{-0}= c_1 -c_2   (2)

If we add equations (1) and (2) we got:

4 = 2c_1 , c_1 = 2

And solving for c_2 we got:

c_2=3-c_1= 3-2 = 1

So then our general solution is given by:

y(t) = 2e^t -e^{-t}

8 0
3 years ago
I urgently need help!!
STALIN [3.7K]

Answer:

<h3> 4.9 ~cm</h3>

❅❅❅❅❅❅❅

<h3>✰<u>Using the intersecting chord theorem:-</u></h3>
  • x(10)=7(7)
  • 10x=49
  • x=49/10
  • =49

✩★✩★✩★✩★✩★✩

hope it helps...

have a great day!!

5 0
3 years ago
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