well, 6.2% of 4,300 can't be over half. she has made a calculation error, and the real answer is (this is where the mistake was made) 4,300 * 0.062 (not 6.2, because percents are always divided by 100 to make them into a usable number), which is equal to $266.60.
Answer:
0.0208<p<0.0592
Step-by-step explanation:
-Given the sample size is 400 and the desired proportion is 16.
-The confidence interval can be determined as follows:

#We the use this proportion to find the CI at 95%:
![CI=0.04\pm 1.96\times \sqrt{\frac{0.04(1-0.04)}{400}}\\\\=0.04\pm 0.0192\\\\=[0.0208,0.0592]](https://tex.z-dn.net/?f=CI%3D0.04%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.04%281-0.04%29%7D%7B400%7D%7D%5C%5C%5C%5C%3D0.04%5Cpm%200.0192%5C%5C%5C%5C%3D%5B0.0208%2C0.0592%5D)
Hence, the 95% confidence interval is 0.0208<p<0.0592
Hoarder of erasers :o
Is this suppose to be a riddle or sum
-7/9 is repeating
42/50 is terminating
-1/125 is terminating
-77/600 is repeating
179/200 is terminating
5/11 is terminating
The way to figure this out is just by dividing the Numerator (top number) by the denomiter (bottom number)
Example 5÷11=.45454545 repeating