Answer:
16ᵗʰ Term of the sequence is 263
Step-by-step explanation:
Here,
First Term = a₁ = 8
Second Term = a₂ = 25
Third Term = a₃ = 42
Now,
Common Difference (d)
d = a₂ - a₁ = 25 - 8 = 17
d = a₃ - a₂ = 42 - 25 = 17
Here, Common Difference is same everywhere
Now, For 16ᵗʰ term, n = 16
<em>aₙ = a + (n - 1)d</em>
a₁₆ = 8 + (16 - 1) × 17
a₁₆ = 8 + 15 × 17
a₁₆ = 8 + 255
a₁₆ = 263
Thus, 16ᵗʰ Term of the sequence is 263
<u>-TheUnknownScientist</u>