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Serggg [28]
3 years ago
10

List the fractions 7/12 ,5/6 , 3/4 , 7/8 from least to greatest

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

Step-by-step explanation:

When using the model bar

7/12 is less than alll of them

The order from least to greatest is

7/12, 3/4, 5/6, and 7/8

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gxg=g^2
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7xg=7g
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g^2-2g-7g+14   then simplify   g^2-9g+14   is the answer
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3 years ago
In two hours Ron read 60 pages of a novel. If the book is 240 pages long, what is the total time that Ron will read at that rate
PilotLPTM [1.2K]

Answer: 4 hours

Step-by-step explanation: you have to divide 240 by 60 which is 4

If this is too hard for you remember you can divide 24 by 6 and get the same answer hope this helps mark me brainliest if it helped

3 0
4 years ago
75 feet of PVC pipe for $111.50 OR 100 feet of PVC pipe for $135.25
kozerog [31]

Answer:

100 Feet of PVC for 135.25

Step-by-step explanation:

If you had 75 feet of PVC and paid 111.50 you would pay 1.48 a foot for each PVC but if you paid 135.25 for 100 feet you would pay 1.35 a foot which in turn would become cheaper.  

7 0
3 years ago
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5 0
3 years ago
Read 2 more answers
Suppose that a researcher is planning a new study on hemoglobin levels amongst women under 25 years old. Previous research sugge
Mariulka [41]

Answer:

A sample size of at least 531 is required.

Step-by-step explanation:

We are lacking the confidence level to solve this question, so i am going to use a 90% confidence level.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Find the required sample size for the new study.

A sample size of at least n is required.

n is found when M = 0.05

We have that \sigma = 0.7

So

M = z*\frac{\sigma}{\sqrt{n}}

0.05 = 1.645*\frac{0.7}{\sqrt{n}}

0.05\sqrt{n} = 1.645*0.7

\sqrt{n} = \frac{1.645*0.7}{0.05}

(\sqrt{n})^{2} = (\frac{1.645*0.7}{0.05})^{2}

n = 530.4

Rounding up

A sample size of at least 531 is required.

5 0
3 years ago
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