Answer:
multiply each by -1
-5/6 x -1 = 5/6
-7 3/8 x -1 = 7 3/8
-3/11 x -1 = 3/11
Step-by-step explanation:
Answer: 80
Step-by-step explanation:
Multiple 8 x 10
Answer:
1296√3 cubic units
Step-by-step explanation:
The volume of the prism will be the product of its base area and its height. Since it circumscribes a sphere with diameter 12, that is the height of the prism.
The central cross section of the sphere is a circle of radius 6, and that will be the size of the incircle of the base. That is, the base will have an altitude of 3 times that incircle radius, and an edge length of 2√3 times that incircle radius. Hence the area of the triangular base is ...
B = (1/2)(6×2√3)(6×3) = 108√3 . . . . . square units
The volume of the prism is then ...
V = Bh = (108√3)(12) = 1296√3 . . . cubic units
_____
<em>Comment on the geometry</em>
The centroid of an equilateral triangle is also the incenter and the circumcenter. The distance of that center from any edge of the triangle is 1/3 the height of the triangle. So, for an inradius of 6, the triangle height is 3×6 = 18. The side length of an equilateral triangle is 2/√3 times the altitude, so is 12√3 units for this triangle.
W = 3A - 6
W = 33
33 = 3A - 6
33 + 6 = 3A
39 = 3A
39/3 = A
13 = A.....he is 13
Answer: C
Step-by-step explanation:
For this problem, we need to know the standard form of a sine function and the meaning of each part.
Standard form: ![y=asin[b(x-h)]+k](https://tex.z-dn.net/?f=y%3Dasin%5Bb%28x-h%29%5D%2Bk)
a=amplitude
b=period
h=phase shift
k=vertical replacement/shifting
Now that we know the standard form and the components, we know that we can forget about k and plug in 0 for h. This would leave us with ![y=asin[b(x)]](https://tex.z-dn.net/?f=y%3Dasin%5Bb%28x%29%5D)
. We know that the amplitude is 2, therefore, a=2. To find the period, you divide 2π by the given period. 
, therefore, b=1/2.
[plug in a=2]
![y=2sin[b(x)]](https://tex.z-dn.net/?f=y%3D2sin%5Bb%28x%29%5D)
[plug in b=1/2]
Therefore, C is the correct answer.
