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3 years ago

In a flower garden, there are 4 tulips for every 9 daisies. If there are 24 tulips, how many daisies are there?

Mathematics

2 answers:

Svet_ta [14]3 years ago

8 0

Answer:

Step-by-step explanation:

For 4 to get to 24, you multiply by 6.

4 x 6 = 24

9 x 6 = 54

PtichkaEL [24]3 years ago

3 0

Answer:

B 52 hope this helps!!!!

Step-by-step explanation:

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leonid [27]

Answer:

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Step-by-step explanation:

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2 years ago

Solve the equations using addition or subtraction.<br> 5.5=-2+d

tia_tia [17]

Answer: d=7.5

Step-by-step explanation: 5.5=−2+d d−2+2=5.5+2 d=7.5

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2 years ago

A man shares a $1,200,00 inheritance between his 3 sons in ratio 1: 3: 6. Calculate the difference between the largest share and

soldi70 [24.7K]

A man's inheritance money = $1200

Given :

He shared his inheritance between his 3 sons in the ratio 1:3:6

Then, the money the first son got :

$= \tt \frac{1}{10} \: of \: 1200$

$=\tt \frac{1}{10} \times 1200$

$=\tt \frac{1 \times 120}{10}$

$= \tt \frac{1200}{10}$

$\color{plum} =\tt\$ \: 120$

▪︎Thus, the first son inherited $120.

Money the second son got :

$= \tt \frac{3}{10} \: of \: 1200$

$= \tt \frac{3}{10} \times 1200$

$=\tt \frac{3 \times 1200}{10}$

$= \tt \frac{3600}{10}$

$\color{plum} =\tt \$360$

▪︎Thus, the second son inherited $360.

Money the third son got :

$=\tt \frac{6}{10} \: of \: 1200$

$=\tt \frac{6}{10} \times 1200$

$= \tt \frac{6 \times 1200}{10}$

$= \tt \frac{7200}{10}$

$\color{plum} = \tt\$720$

▪︎Thus, the third son inherited $720.

We know that :

The largest share = $720

The smallest share = $120

Difference between the largest and smallest share :

$= \tt720 - 120$

$\color{hotpink}\tt = 600$

<h3> ●=> Therefore :</h3>

▪︎<em>The difference between the largest and smallest share = 600</em>

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3 years ago

17. Simplify (3 × 22) ÷ 6 + [28 – (4)2] = ?

Effectus [21]

Answer:

Step-by-step explanation:

(3*22=66) / 6 + [28n - (4)2=20]

66 /6 = 11+ [20]

11+20= 31

7 0

3 years ago

Part a at what speed v should an archerfish spit the water to shoot down an insect floating on the water surface located at a di

loris [4]

3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.

The droplet's horizontal velocity will be:
V/2.

So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6

Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =

8 0

3 years ago