Question

The circle below is centered at the origin and has a radius of 4. What is its

Answer 1

Answer:

Step-by-step explanation:

The standard form of a circle's equation is

$(x-h)^2+(y-k)^2=r^2$ where h and k are the circle's center and r is the radius. We are told, and we can see, that the center of the circle is (0, 0) so h = 0 and k = 0. The radius, given as 4, goes into the equation squared, so the equation is

$(x-0)^2+(y-0)^2=16$ which simplifies down to

$x^2+y^2=16$, choice C.

Answer 2

Answer is: x2+y2=16!!!