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dmitriy555 [2]
3 years ago
7

Which function is the inverse of 2) = 2x + 32 (x) = –2x+3 () = 2x+3

Mathematics
1 answer:
Westkost [7]3 years ago
7 0
Ahhh yes I did I was like I was just trying not to get it to the truck meet up there I was like oh oh my boy is I wanna is
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181 is 22% of what number?
baherus [9]

Answer:

Step-by-step explanation:822.73

6 0
3 years ago
Read 2 more answers
A student draws several cards from a deck of 10 unique cards.
egoroff_w [7]

Answer:

There are 210 different ways that 4 cards can be drawn.

There are 252 different ways that 5 cards can be drawn.

There are 120 different ways that 7 cards can be drawn.

Step-by-step explanation:

Use the combination formula

10C4 =210

10C5 = 252

10C7 = 120

6 0
2 years ago
Solve using substitution<br> y=3x-5<br> 2x+5y=-42
Paul [167]

Answer:

Solution point is (-1,-9)

Step-by-step explanation:

Put the value of y in the first equation into the second equation.

  • 2x + 5(3x - 5) = - 42            Remove the brackets on the left
  • 2x + 15x - 25 = - 42            Combine like terms on the left
  • 17x - 25 = - 42                     Add 25 to both sides
  • 17x - 25 + 25 = - 42 + 25    Do the addition
  • 17x = - 17                              Divide by 17
  • 17x/17 = -17/17                      Do the division
  • x = - 1    

=======

Solve for y

  • y = 3x - 6
  • x = -1
  • y = 3(-1) - 6
  • y = -3 - 6
  • y = - 9
6 0
3 years ago
30 POINTS!! ASAP! PLS SHOW WORK
sp2606 [1]

Answer:

QII

Step-by-step explanation:

We can use the acronym: ASTC or All Students Take Calculus.

The first letter of each word tells us details within a certain quadrant.

All trig functions in QI will be positive.

Only sine (and cosecant) will be positive in QII.

Only tangent (and cotangent) will be positive in QIII.

And only cosine (or secant) will be positive in QIV.

We know that tan(θ)<0. In other words, it's negative.

So, it our angle θ <em>cannot</em> be in QI or QIII.

We also know that cos(θ)<0.

So, this removes QIV, since in QIV, cosine is positive.

Therefore, the only choices that remains is QII.

In QII, sine is positive, tangent is negative, and cosine is negative.

This fits all our conditions, so θ is in QII.

And we're done!

3 0
3 years ago
May I have help to figure out how to do this? It is confusing! :(
RSB [31]

Answer:

it should be 80%

Step-by-step explanation:

I hope this helps

3 0
2 years ago
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